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professor190 [17]
3 years ago
10

lisa gives child (x) and adult (y) haircuts in her salon. she charges $10 for a child and 40$ for an adult haircut. her goal is

to make at least 1000$ per week and work no more than 40 hours. the shaded region of the graph represents the possible combinations of adult and child haircuts that will allow her to meet her goal. which combination represents her maximum profit?
Mathematics
1 answer:
tatyana61 [14]3 years ago
7 0

Answer: (possible answer)

Lisa needs to cut 20 adult's hair then she would have 800$ and 20 children's hair that would give her 200$

1 hour : Adult 40$

2 hour : child  50$

3 hour : Adult 90$

4 hour : child 100$

5 hour : Adult 140$

6 hour : Child 150$

7 hour : Adult 190$

8 hour : child 200$

9 hour : Adult 240$

10 hour : child 250$

11 hour : adult 290$

12 hour : child 300$

13 hour : adult 340$

14 hour : child  350$

15 hour : adult 390$

16 hour : child 400$

17 hour : adult 440$

18 hour : child 450$

19 hour : adult 490$

20 hour : child 500$

21 hour : adult 540$

22 hour : child 550$

23 hour : adult 590$

24 hour : child 600$

25 hour : adult 640$

26 hour : child 650$

27 hour : adult 690$

28 hour : child 700$

29 hour : adult 740$

30 hour : child 750$

31 hour : adult 790$

32 hour : child 800$

33 hour : adult 840$

34 hour : child 850$

35 hour : adult 890$

36 hour : child 900$

37 hour : adult 940$

38 hour : child 950$

39 hour : adult 990$

40 hour : child 1000$

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Answer:

B 98

Step-by-step explanation:

4*7=28  times 3 = 84

3.5*4=14

84+14=98

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kotykmax [81]

Answer:

B. \frac{60 hours}{1} \times \frac{1 day}{24 hours}

Step-by-step explanation:

Converting 60 hours to days:

24 hours = 1 day

60 hours = x day

Cross multiply

24 hours \times x = 60 hours \times 1 day

Divide both sides by 24 hours

x = \frac{60 hours \times 1 day}{24 hours}

Thus,

\frac{60 hours \times 1 day}{24 hours} = \frac{60 hours}{1} \times \frac{1 day}{24 hours}

The expression that shows how to convert 60 hours to days is:

\frac{60 hours}{1} \times \frac{1 day}{24 hours}

5 0
3 years ago
If 3x - 6 = 21, what is the value of x - 2 ?
lora16 [44]
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3 years ago
The owner of an automobile insures it against damage by purchasing an insurance policy with a deductible of 250. In the event th
choli [55]

Answer:

Step-by-step explanation:

From the given information:

The uniform distribution can be represented by:

f_x(x) = \dfrac{1}{1500} ; o \le x \le   \  1500

The function of the insurance is:

I(x) = \left \{ {{0, \ \ \ x \le 250} \atop {x -20 , \ \  \ \ \ 250 \le x \le 1500}} \right.

Hence, the variance of the insurance can also be an account forum.

Var [I_{(x}) = E [I^2(x)] - [E(I(x)]^2

here;

E[I(x)] = \int f_x(x) I (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250) \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^2}{2} \Big |^{1500}_{250}

\dfrac{5}{12} \times 1250

Similarly;

E[I^2(x)] = \int f_x(x) I^2 (x) \ sx

E[I(x)] = \dfrac{1}{1500} \int ^{1500}_{250{ (x- 250)^2 \ dx

= \dfrac{1}{1500 } \dfrac{(x - 250)^3}{3} \Big |^{1500}_{250}

\dfrac{5}{18} \times 1250^2

∴

Var {I(x)} = 1250^2 \Big [ \dfrac{5}{18} - \dfrac{25}{144}]

Finally, the standard deviation  of the insurance payment is:

= \sqrt{Var(I(x))}

= 1250 \sqrt{\dfrac{5}{48}}

≅ 404

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3 years ago
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