Line JK passes through points J(-4,-5) and K(-6,3). If the equation of the line is written in slope-intercept form, y-mx+b, what

Question

skelet666 [1.2K]

3 years ago

13

Line JK passes through points J(-4,-5) and K(-6,3). If the equation of the line is written in slope-intercept form, y-mx+b, what

is the value of b?

Mathematics

2 answers:

Olegator [25] · Answer 1 · 2022-02-20T03:24:03+03:00

Olegator [25]3 years ago

6 0

Answer:

Step-by-step explanation:

A) -21

Ksju [112] · Answer 2 · 2022-02-20T00:59:46+03:00

Ksju [112]3 years ago

4 0

$y=mx+b \\ \\
(x,y)=(-4,-5) \hbox{ and } (x,y)=(-6,3) \\ \Downarrow \\
-5=-4m+b \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \times (-3) \\
3=-6m+b \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\times 2 \\ \\
15=12m-3b \\
\underline{6=-12m+2b} \\
21=-b \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\times (-1) \\
\boxed{b=-21}$

The value of b is -21.