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dem82 [27]
3 years ago
7

Seetha drove to work at 30 miles per hour. How fast would she need to drive home for the average speed for her round trip commut

e to be 60 miles per hour
Mathematics
1 answer:
Sophie [7]3 years ago
8 0

Answer:

40

Step-by-step explanation: Total distance = 60 miles

Total time = 30 / 30 + 30/60 = 3/2

Avg. speed = 40.

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What is the measure of AngleSRT?
Fofino [41]

Answer:

Angle SRT is equal to 79 degrees

Step-by-step explanation:

The reason this is so is because for every single triangle all the angles must add up to 180 degrees. So take 180 minus angle T, and then minus angle S and you get 79.

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2 years ago
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ayuda porfavor cuanto es h+3cm=? y cuanto es b+4cm=? y cual seria el resustado de las dos calculacion
katrin [286]

GOOD MORNING,

HAVE A GREAT DAY AHEAD

4 0
2 years ago
What is the product?
Olenka [21]

The value of the product expression (-2x-9y²)(-4x-3) is 8x² + 6x + 27y² + 36xy²

<h3>How to evaluate the product?</h3>

The expression is given as:

(-2x-9y²)(-4x-3)

Expand the expression

8x² + 6x + 27y² + 36xy²

Hence, the value of the product expression (-2x-9y²)(-4x-3) is 8x² + 6x + 27y² + 36xy²

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brainly.com/question/10873737

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3 0
2 years ago
A football is thrown from the top of the stands, 50 feet above the ground at an initial velocity of 62 ft/sec and at an angle of
Anvisha [2.4K]

a. i. The parametric equation for the horizontal movement is x = 43.84t

ii. The parametric equation for the vertical movement is y = 50 + 43.84t

b. the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

<h2>a. Parametric equations</h2>

A parametric equation is an equation that defines a set of quantities a functions of one or more independent variables called parameters.

<h3>i. Parametric equation for the horizontal movement</h3>

The parametric equation for the horizontal movement is x = 43.84t

Since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the horizontal component of the velocity is v' = vcosФ.

So, the horizontal distance the football moves in time, t is x = vcosФt

= vtcosФ

= 62tcos45°

= 62t × 0.7071

= 43.84t

So, the parametric equation for the horizontal movement is x = 43.84t

<h3>ii Parametric equation for the vertical movement</h3>

The parametric equation for the vertical movement is y = 50 + 43.84t

Also, since

  • the angle of elevation is Ф = 45° and
  • the initial velocity, v = 62 ft/s,

the vertical component of the velocity is v" = vsinФ.

Since the football is initially at a height of h = 50 feet, the vertical distance the football moves in time, t relative to the ground is y = 50 + vsinФt

= 50 + vtcosФ

= 50 + 62tsin45°

= 50 + 62t × 0.7071

= 50 + 43.84t

<h3>b. Location of football at maximum height relative to starting point</h3>

The location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

Since the football reaches maximum height at t = 1.37 s

The x coordinate of its location at maximum height is gotten by substituting t = 1.37 into x = 48.84t

So, x = 43.84t

x = 43.84 × 1.37

x = 60.0608

x ≅ 60.1 ft

The y coordinate of the football's location at maximum height relative to the ground is y = 50 + 48.84t

The y coordinate of the football's location at maximum height relative to the starting point is y - 50 = 48.84t

So,  y - 50 = 48.84t

y - 50 = 43.84 × 1.37

y - 50 = 60.0608

y - 50 ≅ 60.1 ft

So, the location of the football at its maximum height relative to the starting point is (60.1 ft, 60.1 ft)

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5 0
2 years ago
Find the image of triangle GHJ under the translation of (X,Y) ——&gt; ( x-1, y-8)
MAVERICK [17]

Answer:

triangle KLM

Step-by-step explanation:

Take one point on the initial triangle and move it according to the given translation to locate the image. I used point G. Its coordinate plot is at

(2,3). I perform the operation of the given translation to this. (X1-X2, y1-y2).

So, (2-1, 3-8). The new coordinates will be (1,-5) and the only triangle with these coordinates is triangle KLM.

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3 years ago
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