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Lana71 [14]
3 years ago
11

Solve for x Write both solutions, seperated by a comma 4x^2+5x+1=0

Mathematics
1 answer:
stiv31 [10]3 years ago
5 0

Answer:

-1/4 , -1

Step-by-step explanation:

I solved it using Factorization method and Quadratic Equation .

Factorization Method

4x^2+5x+1=0\\Write +5x- as- a -difference(write+5x-using- two- numbers -in-which-their-sum-is ; 5-and-their-product-is ; 4)\\4x^{2} +4x+1x+1=0\\Factorize-out-common-terms\\4x(x+1)+1(x+1)=0\\Factor-out-(x+1)\\(4x+1)(x+1)=0\\4x+1 =0    \\x+1=0\\4x=0-1\\x =0-1\\4x =-1\\x =-1\\4x=-\frac{1}{4} \\\\Answer = -1/4 , -1

Quadratic Equation

4x^2+5x+1=0\\a = 4\\b =5\\c = 1\\\\x =\frac{-b\±\sqrt{b^2 -4ac} }{2a} \\\\x = \frac{-(5)\±\sqrt{(5)^2-4(4)(1)} }{2(4)} \\\\x = \frac{-5\±\sqrt{25-16} }{8} \\\\x = \frac{-5\±\sqrt{9} }{8} \\\\x = \frac{-5\±3}{8} \\\\x =\frac{-5+3}{8} \\\\x = \frac{-5-3}{8} \\\\x = \frac{-2}{8} \\\\x = \frac{-8}{8} \\\\x = -\frac{1}{4} \\x=-1

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Step-by-step explanation:

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* In Δ ABC

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