• Use slope to graph linear equations in two variables.
• Find the slope of a line given two points on the line.
• Write linear equations in two variables.
• Use slope to identify parallel and perpendicular lines.
• Use slope and linear equations in two variables to model and solve real-life problems.
2
Answer:
The distance added to each dimension is 2 yards.
Step-by-step explanation:
The initial dimensions of the rectangular fence is 8 yards by 4 yards.
The initial area of the rectangular fence = area of a rectangle
area of a rectangle = length x width
So that,
The initial area of the fence = 8 x 4
= 32
The initial area of the fence is 32 square yards.
But, with the new dimensions, area = 60 square yards.
(4 + x) x (8 + x) = 60
+ 12x + 28 = 60
+ 12x - 32 = 0
(x + 14) = 0 or (x - 2) = 0
x = -14 or x =2
Thus, x = 2
The distance added to each dimension is 2 yards.
The region is in the first quadrant, and the axis are continuous lines, then x>=0 and y>=0
The region from x=0 to x=1 is below a dashed line that goes through the points:
P1=(0,2)=(x1,y1)→x1=0, y1=2
P2=(1,3)=(x2,y2)→x2=1, y2=3
We can find the equation of this line using the point-slope equation:
y-y1=m(x-x1)
m=(y2-y1)/(x2-x1)
m=(3-2)/(1-0)
m=1/1
m=1
y-2=1(x-0)
y-2=1(x)
y-2=x
y-2+2=x+2
y=x+2
The region is below this line, and the line is dashed, then the region from x=0 to x=1 is:
y<x+2 (Options A or B)
The region from x=2 to x=4 is below the line that goes through the points:
P2=(1,3)=(x2,y2)→x2=1, y2=3
P3=(4,0)=(x3,y3)→x3=4, y3=0
We can find the equation of this line using the point-slope equation:
y-y3=m(x-x3)
m=(y3-y2)/(x3-x2)
m=(0-3)/(4-1)
m=(-3)/3
m=-1
y-0=-1(x-4)
y=-x+4
The region is below this line, and the line is continuos, then the region from x=1 to x=4 is:
y<=-x+2 (Option B)
Answer: The system of inequalities would produce the region indicated on the graph is Option B
Answer:I'd sayb
Step-by-step explanation:
Answer:
Step-by-step explanation:
We are to find the equation a line that passes through the point (8, 1) and which is perpendicular to a line whose equation is
.
We know that the slope of line which is perpendicular to another line is the negative reciprocal of the slope of the other line so it will be
.
Then, we will find the y-intercept of the line using the standard equation of a line:
Therefore, the equation of the line will be
.