Simplify this Expression

What is the relationship between x and y

solong [7]

Given:

Given that the table with values of x and y.

We need to determine the relationship between x and y.

Slope:

The slope of the relation can be determined using the formula,

$m=\frac{y_2-y_1}{x_2-x_1}$

Substituting the points (2,11) and (4,9), we get;

$m=\frac{9-11}{4-2}$

$m=\frac{-2}{2}$

$m=-1$

Thus, the slope of the relation is m = -1.

y - intercept:

The y - intercept of the relation is the value of y when x = 0.

Hence, from the table, it is obvious that when x = 0, the value of y is 13.

Thus, the y - intercept of the relation is b = 13.

Relationship between x and y:

The relationship between x and y can be determined using the formula,

$y=mx+b$

Substituting m = -1 and y =13, we get;

$y=-x+13$

Thus, the relationship between x and y is $y=-x+13$

3 0

3 years ago

Mass is the ________(1)________, where as depth is the ________(2)________.

Mice21 [21]

Mass is the amount of matter a certain object has, where as depth is the distance from the topmost part of a certain object that runs down to it's most

6 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Archy [21]

Each quarter of a set of data is denoted by a quartile:

The 25th percentile makes up the first quartile Q1.
The 50th percentile represents the second quartile Q2.
The 75th percentile is the third quartile, or Q3.
Finding the second quartile, Q2, is simple. It divides an ordered data set into upper and lower half and is the median of any data set.

The median of the bottom half, excluding the value of Q2, makes up the first quartile, or Q1. The median of the upper half, excluding the value of Q2, makes up the third quartile, or Q3.

Sort the values in your data set from lowest to highest.
the median, please. Q2 stands for the second quartile.
Divide the ordered data collection in half at Q2.
The median of the lower half of the data makes up the lower quartile Q1.
The median of the data's upper half represents the upper quartile Q3.
When determining the first and third quartiles, omit the median if the size of the data set is unusual.
The median, if the size of the data collection is even, is the average of the middle two values. Add the two figures together, then divide by two. The value of the median, which divides the data set into lower and higher half, is

How to Find Interquartile Range
The interquartile range IQR is the range in values from the first quartile Q1 to the third quartile Q3. Find the IQR by subtracting Q1 from Q3.

IQR = Q3 - Q1

How to Find the Minimum

The minimum is the smallest value in a sample data set. Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the minimum is the smallest value x1. The formula for minimum is:

Min=1=min()=1

How to Find the Maximum

The maximum is the largest value in a sample data set.

Ordering a data set from lowest to highest value, x1 ≤ x2 ≤ x3 ≤ ... ≤ xn, the maximum is the largest value xn. The formula for maximum is:

Max==max()=1

How to Find the Range of a Set of Data

The range of a data set is the difference between the minimum and maximum. To find the range, calculate xn minus x1.

=−1

So to Answer your question

6 0

1 year ago

Find the circumference of the circle.

Vesna [10]

Assuming 13 is the radius the answer is 81.64cm

5 0

3 years ago

How dose north america achieve 480VAC with 3 pole 120VAC

makvit [3.9K]

Answer:

There are a variety of factors driving the

adoption of 415/240VAC distribution. First,

distributing at these increased voltages

enables overall efficiency to be enhanced

by eliminating the need for a voltage

transformation along the power path. For

example, in a 415V system, the L-N voltage

is 240V, which is compatible with most all IT

loads. By shifting the UPS output distribution

voltage to 415/240 V three-phase (L-L/

L-N), most of the existing servers today can

be powered with 240V single-phase (L-N)

without any intermediate transformation.

Removing the need for a transformer

streamlines the power path and can increase

efficiency approximately 1.5 percent.

The adoption of a 415/240VAC distribution

model also can yield additional savings at

the device-level in the form of increased

efficiency for server power supplies. As

previously mentioned, today’s power

supplies can handle a wide range of incoming

voltages. Based on the actual voltage being

fed into the power supply, efficiencies can

range from as low as 80 percent (at 100V

nominal) to as much as 94 percent (at 240V

nominal) across all manufacturers.

Furthermore, while the typical efficiency

differential between 240V and 208V gained

at the server power supply today is a relatively

minimal, only 0.3 percent across most of

the load range, the efficiency differential

between 240V and 120V servers can be as

much as 2 percent for a given power supply.

It is this value that often gets overstated by

some manufacturers when comparing 415V

distribution to “traditional methods,” as

there are relatively few servers or peripherals

installed today that are operating at 120V.

Step-by-step explanation:

7 0

3 years ago