5y+2(3y-1)=__y-(y+2)
5y+6y-2=__y-y-2
11y-2+2+y=__y
12y=___y
so 12
Answer:
1) 5 2) 6 3) 1.25 or -1.75
Step-by-step explanation:
1. x^2 - 25 = 0
x^2 - 25 = 0
First, add 25 to both sides!
x^2 = 25
Now square root both sides.
x = 5
2. (x-2)^2 = 16
First, square root both sides.
(x-2) = 4
Add 2 on both sides.
(x) = 6
x = 6
3. Quadratic Formula = -b ±
/ 2a
Substitute in:
-6 ±
/ 2(2)
-6±
/ 4
Both forms:
-6 +
/ 4
5 / 4 = 1.25
Negative:
-6 - 1 / 4
-7 / 4 = -1.75
C should be your answer:))))
Answer:
Step-by-step explanation:
Explanation:
The
average rate of change
of g(x) over an interval between 2 points (a ,g(a)) and (b ,g(b) is the slope of the
secant line
connecting the 2 points.
To calculate the average rate of change between the 2 points use.
∣
∣
∣
∣
∣
¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯
a
a
g
(
b
)
−
g
(
a
)
b
−
a
a
a
∣
∣
∣
−−−−−−−−−−−−−−−
g
(
6
)
=
6
2
−
6
+
3
=
33
and
g
(
4
)
=
4
2
−
4
+
3
=
15
Thus the average rate of change between (4 ,15) and (6 ,33) is
33
−
15
6
−
4
=
18
2
=
9
This means that the average of all the slopes of lines tangent to the graph of g(x) between (4 ,15) and (6 ,33) is 9
The answer to the question you are looking for is right in front of u