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Rina8888 [55]
2 years ago
9

Based only on the information given in the diagram, which congruence

Mathematics
1 answer:
professor190 [17]2 years ago
8 0

The congruence theorems or postulates that could be given as reasons why ACDE=AOPQ are:

  • AAS
  • HA
  • ASA

<h3>What is this  congruence theorems about?</h3>

Note that in the diagram, there has been given one side that is congruent to its other corresponding side and as such, it has remove the option or postulates that needs the HL and SAS sides.

Conclusively, when all three angles are said to be congruent and when they have one side (known as the hypotenuse), one can use the congruence theorems or postulates of  AAS, HA and ASA.

Learn more about congruence theorems from

brainly.com/question/10609346

#SPJ1

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Answer:

Equivalent representations of percent problems

Step-by-step explanation:

3 0
3 years ago
If 1 inch = 50 miles how many miles is 8.5 in
GenaCL600 [577]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ 8.5 in = 425 miles

If 1 mi = 50 inches, multiply by 8.5:

50 x 8.5 = 425

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

7 0
3 years ago
Which statements about the local maximums and minimums for the given function are true? Choose three options.
Nostrana [21]

Answer:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.

Step-by-step explanation:

The true statements are:

Over the interval [2, 4], the local minimum is –8.

Over the interval [3, 5], the local minimum is –8.

Over the interval [1, 4], the local maximum is 0.  

Lets discuss each option one by one:

Over the interval [1, 3], the local minimum is 0

This is a false statement. Look at the graph. The minimum point given is (3.4,-8). Therefore the local minimum is -8 not 0

Over the interval [2, 4], the local minimum is –8.

This statement is true because the given minimum point is(3.4, -8). Thus the  local minimum is -8 which is true

Over the interval [3, 5], the local minimum is –8.

According to the given minimum point, the local minimum  is -8 which is true

Over the interval [1, 4], the local maximum is 0.

Look at the graph. The maximum point given is (2,0). Thus this statement is true because local maximum is 0.

Over the interval [3, 5], the local maximum is 0.

This is a false statement because there is no maximum point

8 0
3 years ago
Read 2 more answers
How do i complete the square for this equation ? x^2+ 8x+y^2-2y=64
liraira [26]
<span>Simplifying x2 + 8x + y2 + -2y = 64
 Reorder the terms: 8x + x2 + -2y + y2 = 64 Solving 8x + x2 + -2y + y2 = 64 Solving for variable 'x'.
 Reorder the terms: -64 + 8x + x2 + -2y + y2 = 64 + -64
  Combine like terms: 64 + -64 = 0 -64 + 8x + x2 + -2y + y2 = 0


 The solution to this equation could not be determined.</span>
4 0
3 years ago
Solve and reduce to lowest terms:<br> 6 / 11 x 1 / 3
zysi [14]

Answer:

2/11

Step-by-step explanation:

6/11 x 1/3 =

6/33 =

2/11

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

5 0
3 years ago
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