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2 years ago

Based only on the information given in the diagram, which congruence

Mathematics

1 answer:

professor190 [17]2 years ago

8 0

The congruence theorems or postulates that could be given as reasons why ACDE=AOPQ are:

<h3>What is this congruence theorems about?</h3>

Note that in the diagram, there has been given one side that is congruent to its other corresponding side and as such, it has remove the option or postulates that needs the HL and SAS sides.

Conclusively, when all three angles are said to be congruent and when they have one side (known as the hypotenuse), one can use the congruence theorems or postulates of AAS, HA and ASA.

Learn more about congruence theorems from

brainly.com/question/10609346

#SPJ1

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How many full 5/8 ft pieces of wood can you cut from a board that is 458 feet long?

tankabanditka [31]

Answer:

732 pieces

Step-by-step explanation:

458/5/8

= 458* 8/5= 732 pieces

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Can you use the ASA postulate or the ASA theorem to prove the triangles are congruent?

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n = 23 H0: σ2 ≥ 66 s2 = 60 Ha: σ2 < 66 The test statistic has a value of _____. a. 24.20 b. 24.00 c. 20.91 d. 20.00

Arada [10]

Answer:

$\chi^2 =\frac{23-1}{66} 60 =20.00$

d.20.00

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=23$ represent the sample size

$\alpha$ represent the confidence level

$s^2 =60$ represent the sample variance obtained

$\sigma^2_0 =66$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance is less than 66, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 66$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{23-1}{66} 60 =20.00$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case 23-1=22. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

The best option is:

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4 years ago

What is 0.1554 divided by 74?

umka2103 [35]

Answer:

0.0021

Step-by-step explanation:

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