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cluponka [151]
3 years ago
6

Jamal puts $100 in an account that does not earn any interest. Every month after that, he deposits the same amount of money. Thi

s sequence represents his account balance for the first few months. $100, $125, $150, What is the explicit formula in function form for the amount of money in his account at the beginning of month n?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

Tn = 75+25n

Step-by-step explanation:

The balance are in arithmetic progression

$100, $125, $150...

The formula for calculating the nth term of the sequence is expressed as;

Tn = a+(n-1)d

a =100

d = 125 - 100 = 150 - 125

d = 25

n is the number of terms

Substitute

Tn = 100+(n-1)*25

Tn = 100 + 25n-25

Tn = 75+25n

Hence the nth term of the sequence is Tn = 75+25n

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Roberta has $10,540 to invest. She plans to invest her money in certificates of deposit (CDs) that have 2.1% interest, a stock p
ira [324]

Answer:

The amount invested in CDs is  $1,340

The amount invested in the stock portafolio is $6,900

The amount invested in the saving accounts is $2,300

Step-by-step explanation:

Let

x ---->the amount invested in CDs at 2.1%

y ---> the amount invested in the stock portfolio at 2.5%

z ---> the amount invested in the savings account at 1.5%

x+y+z=10,540 ----> equation A

z=\frac{1}{3}y ----> equation B

substitute equation B in equation A

x+y+\frac{1}{3}y=10,540

x+\frac{4}{3}y=10,540

x=10,540-\frac{4}{3}y ----> equation C

we know that

The total interest earned by the three amount must be equal to $231.69

so

0.021x+0.025y+0.015z=231.69 ----> equation D

substitute equation B and equation C in equation D

0.021(10,540-\frac{4}{3}y)+0.025y+0.015(\frac{1}{3}y)=231.69

solve for y

221.34-0.0315y+0.025y+0.005y=231.69

0.0015y=231.69-221.34

0.0015y=10.35

y=\$6,900

<em>Find the value of x</em>

x=10,540-\frac{4}{3}(6,900)

x=\$1,340

<em>Find the value of z</em>

z=\frac{1}{3}(6,900)

z=\$2,300

7 0
4 years ago
The Millers plan on retiring soon. When they were first married they purchased 1,000 shares in a mutual fund that was at that ti
kozerog [31]

Answer: There is 680% increase for the fund.

Step-by-step explanation:

Since we have given that

Number of shares they purchased = 1000

Cost of per share at the time of their marriage = $10

So, Amount of fund will be

1000\times 10=\$10000

Cost per share after 30 years = $78

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78\times 1000=\$78000

Percentage of increase for the fund will be given as

\frac{78000-10000}{10000}\times 100=680\%

Hence, there is 680% increase for the fund.

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3 years ago
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Answer:

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<u>1 and 2/3 minus 4/5</u>

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How do you write 26.2 as a mixed number in simplest form
egoroff_w [7]
26 = 26
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