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cluponka [151]
3 years ago
6

Jamal puts $100 in an account that does not earn any interest. Every month after that, he deposits the same amount of money. Thi

s sequence represents his account balance for the first few months. $100, $125, $150, What is the explicit formula in function form for the amount of money in his account at the beginning of month n?
Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

Tn = 75+25n

Step-by-step explanation:

The balance are in arithmetic progression

$100, $125, $150...

The formula for calculating the nth term of the sequence is expressed as;

Tn = a+(n-1)d

a =100

d = 125 - 100 = 150 - 125

d = 25

n is the number of terms

Substitute

Tn = 100+(n-1)*25

Tn = 100 + 25n-25

Tn = 75+25n

Hence the nth term of the sequence is Tn = 75+25n

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A line passes through (−1, 7) and (2, 10).
Murljashka [212]
The formula is y=mx+b
To get the slope or m, use this formula
(the second y minus the first y)/(the second x minus the first x)
Now set it up.
(10-7)/(2--1)
3/3=slope is 1.
y=1x+b

Insert one of the points for x and y.
i will do (-1,7)
7=1(-1)+b
7=-1+b
8=b
Insert this into the final equation:
y=1x+8

Try it out. If you're not sure, try both points. If it works, then you set it up correctly.
6 0
3 years ago
Read 2 more answers
A ball is hurled in the air such that its horizontal (x) and vertical (y) shifts are given by the functions x(t) = 20t and y(t)
Viefleur [7K]

x(t) = 20t

y(t) = 40t - 5t^2

Since we are only interested in comparing the two at time t = 5 seconds, we plug in 5 everywhere we see the variable t and then compare x and y

x(5) = 20(5) becomes x(5) = 100

y(5) = 40(5) - 5(5)^2 becomes y(5) = 200 - 125 and then y(5) = 75

The ratio of y to x can be expressed as: y/x, so we can say the ratio is equal to 75/100 or 0.75

Answer: 0.75

7 0
4 years ago
Solve this equation -k/5=7/10
liberstina [14]
-\dfrac{k}{5}=\dfrac{7}{10}\\
-10k=35\\
k=-3.5
4 0
3 years ago
Givers the linear sequence,<br> -2,7,X,Y, 2... Find the value of<br> Z.
Harrizon [31]

Answer:

Z = 34

Step-by-step explanation:

From the series, we have that:

a = -2

a + d = 7

Hence, -2 + d = 7

∴ d = 7 + 2 = 9

a + 2d = X; a + 3d = Y and a + 4d = Z

-2 + 4(9) = Z

∴ Z = 36 - 2 = 34

7 0
3 years ago
On the 1st January 2014 Carol invested some money in a bank account.
Ghella [55]

Answer:

\large \boxed{\text{\pounds 23 360.00}}

Step-by-step explanation:

The formula for the accrued amount from compound interest is

A = P \left(1 + \dfrac{r}{n}\right)^{nt}

1. Amount in account on 1 Jan 2015

(a) Data:

a = £23 517.60

r = 2.5 %

n = 1

t = 1 yr

(b) Calculations:  

r = 0.025

\begin{array}{rcl}23517.60 & = & P\left (1 + \dfrac{r}{n}\right)^{nt}\\\\& = & P\left (1 + \dfrac{0.025}{1}\right)^{1\times1}\\\\& = & P (1 + 0.025)\\ & = & 1.025 P\\P & = & \dfrac{23517.60 }{1.025} \\\\& = & 22 944.00 \\\end{array}

The amount that gathered interest was £22 944.00 but, before the interest started accruing, Carol had withdrawn £1000 from the account.

She must have had £23 944 in her account on 1 Jan 2015.

(2) Amount originally invested

(a) Data

A = £23 944.00

\begin{array}{rcl}23 944.00 & = & 1.025 P\\P & = & \dfrac{23 944.00 }{1.025} \\\\& = & \mathbf{23 360.00} \\\end{array}\\\text{Carol originally invested $\large \boxed{\textbf{\pounds23 360.00}}$ in her account.}

3. Summary

1 Jan 2014      P = £23 360.00

1 Jan 2015     A =    23 944.00

     Withdrawal = <u>    -1  000.00 </u>

                     P =     22 944.00

1 Jan 2016    A =    £23 517.60

5 0
3 years ago
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