Question

Does anyone know this??

Answer 1

Answer:

$sinA=\frac{12}{37} \\\\cosA=\frac{35}{37}\\\\ tanA=\frac{12}{35}$

Step-by-step explanation:

In the given triangle we have to find the ratios of $sinA$ ,$cosA$ and $tan A$

Given:

    $Perpendicular= 12\\\\ Base= 35\\\\ Hypotenuse=37$

Ratio of $sinA$

                  $sinA= \frac{Perpendicular}{Hypotenuse} \\\\sinA= \frac{12}{37}$

Ratio of $cosA$

                  $cos A=\frac{Base}{Hypotenuse}\\\\ cosA=\frac{35}{37}$

Ratio of $tan A$

                 $tanA=\frac{Perpendicular}{Base} \\\\tanA=\frac{12}{35}$