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3 years ago

What would you fill in the blank to make the equation have no solution? -2+4x+6=3x+5__?

Mathematics

2 answers:

aleksandrvk [35]3 years ago

6 0

Ok so in order to make it no solution. Both sides need to be equal.

ozzi3 years ago

5 0

Answer:

fnmk;fnhfk;

Step-by-step explanation:

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DOES ANYONE KNOW THE ANSWER PLEASE HELP

lorasvet [3.4K]

Answer:

It should be 4 or (0,4)

Step-by-step explanation:

The y-intercept is just where one of the lines of the graph crosses the y-axis, which in the picture shows it crosses at (0,4)

3 0

3 years ago

I am confused and i dont know how i would do this

Crank

Answer:

5760

Step-by-step explanation:

I do 12 x 12 x 10 x 4= 5760

3 0

3 years ago

Simplify: cos2x-cos4 all over sin2x + sin 4x

GrogVix [38]

Answer:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

Step-by-step explanation:

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}$

Apply formula:

$\cos\left(A\right)-\cos\left(B\right)=-2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$ and

$\sin\left(A\right)+\sin\left(B\right)=2\cdot\sin\left(\frac{A+B}{2}\right)\cdot\sin\left(\frac{A-B}{2}\right)$

We get:

$=\frac{-2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\sin\left(\frac{2x-4x}{2}\right)}{2\cdot\sin\left(\frac{2x+4x}{2}\right)\cdot\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{2x-4x}{2}\right)}{\cos\left(\frac{2x-4x}{2}\right)}$

$=\frac{-\sin\left(\frac{-2x}{2}\right)}{\cos\left(\frac{-2x}{2}\right)}$

$=\frac{-\sin\left(-x\right)}{\cos\left(-x\right)}$

$=\frac{-\cdot-\sin\left(x\right)}{\cos\left(x\right)}$

$=\frac{\sin\left(x\right)}{\cos\left(x\right)}$

$=\tan\left(x\right)$

Hence final answer is

$\frac{\cos\left(2x\right)-\cos\left(4x\right)}{\sin\left(2x\right)+\sin\left(4x\right)}=\tan\left(x\right)$

6 0

3 years ago

Can anyone please answer these for me?

yulyashka [42]

11. y=-3x-5

12. y=-5

13. y= -1/3x+5

14. y=3x-5

3 0

4 years ago

Help me, I don't understand this problem

Crank

Read some notes on reflection. If it asks to reflect it on the x-axis youre going to reflect it either on the bottom or top plane. If it asks to reflect on y-axis youre going to reflect it on either the left or right plane.

5 0

3 years ago