To find where on the hill the canonball lands
So 0.15x = 2 + 0.12x - 0.002x^2
Taking the LHS expression to the right and rearranging we have -0.002x^2 + 0.12x -
0.15x + 2 = 0.
So we have -0.002x^2 - 0.03x + 2 = 0
I'll multiply through by -1 so we have
0.002x^2 + 0.03x -2 = 0.
This is a quadratic eqn with two solutions x1 = 25 and x2 = -40 since x cannot be negative x = 25. The second solution y = 0.15 * 25 = 3.75
The answer is attached, hope this helps!
A; rate of change is the same as slope, so, using the slope formula,

, where

is the slope and

,

,

, and

are the

and

values.
Plug in

points for

and

, water level being the

and time being the

since we're looking for the answer in ft/hr-- you can choose any two, but from the same row.




ft/hr