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solmaris [256]
3 years ago
9

Glucose and hexanoic acid each contain six carbon atoms, but they have completely different properties. Glucose is a nutrient fo

und in food; hexanoic acid is poisonous. Their differences must be due to different __________
Biology
1 answer:
IrinaK [193]3 years ago
7 0

Answer:

functional groups

Explanation:

Functional groups are molecules with specific atoms and have their own chemical properties when attached to some other substances. Glucose is a simple sugar and has an aldehyde group (CHO) as its functional group. The presence of CHO in it makes it be present in food without any harmful impacts. On the other hand, hexanoic acid has COOH (carboxylic group) as its functional group. COOH group has a tendency to donate its protons and become ionized. It is toxic as it is reactive and tends to affect the pH of the food or solution in which it is present.

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if there are 500 people in a population, and 150 are homozygous HbA/hba, 150 are homozygous hbs/hbs, and 200 are heterozygous hb
sineoko [7]

Answer:

0.547

Explanation:

Given -

Total Population - 500

Individuals with homozygous HbA/hbA genotype - 150

Individuals with homozygous hbs/hbs genotype -150

Individuals with heterozygous hba/hbs genotype -  200

Let us assume the given population is in Hardy Weinberg' equilibrium

The frequency of individuals in the given population with homozygous HbA/hba genotype is equal to number of individuals with homozygous HbA/hba genotype divided by total population.

\frac{150}{500} \\= 0.3

The frequency of hba allele is equal to

\sqrt{0.3} \\= 0.5477

3 0
3 years ago
1. Why is the moon’s gravity weaker than Earth’s gravity?
vfiekz [6]

1 The Earth's Moon has considerably less mass than the Earth itself. Not only is the Moon smaller than the Earth but it is only about 60 percent as dense as Earth. Thus the gravitational attraction on the Moon is much less than it is here on Earth and a person weighs less on the Moon

2 The strength of the gravitational force between two objects depends on two factors mass and distance. the force of gravity the masses exert on each other. If one of the masses is doubled the force of gravity between the objects is doubled increases, the force of gravity decreases.

3 If the mass of one of the objects is doubled, then the force of gravity between them is doubled.  If the separation distance between any two objects is tripled (increased by a factor of 3), then the force of gravitational attraction is decreased by a factor of 9 (3 raised to the second power).

4 idk about this one

5 0
3 years ago
What are the levels of organization starting with an electron ending with an organism (plant or animal).
Nitella [24]
Answer:
             Level of organization from electron to an organism is shown in the figure, have a look on it will help you a lot.

5 0
3 years ago
What is the relationship between air pressure and wind velocity?
Pachacha [2.7K]

Explanation:

Velocity refers to how fast the air is moving in distance per unit of time. While pressure is the measure of force applied on an area.

7 0
3 years ago
What is the magnitude of the force exerted by the biceps fbiceps? What is the magnitude of the force exerted by the elbow felbow
Slav-nsk [51]

Answer:

<u> </u><u>The magnitude of the force exerted by the biceps </u>f_b_i_c_e_p_s<u> is 218.38N</u>

<u>The magnitude of the force exerted by the elbow </u>f_e_l_b_o_w<u> is 194.37N</u>

Explanation:

Firstly , lets calculate the magnitude of force exerted by biceps f_b_i_c_e_p_s -

Mass of the forearm=

m_f=1.50kg

Mass of the ball =

m_b_a_l_l=950g

   = 0.950kg

so, weight of the forearm=

w_f=m_f g

weight of the ball=

w_b_a_l_l=m_b_a_l_l g

Now , balancing torque about the elbow , we have-

F_b_i_c_e_p_s\times d_b_i_c_e_p_s= w_f\times\frac{d_b_a_l_l}{2} + w_b_a_l_l\times d_b_a_l_l

(here , distance of the bicep is 2.50cm = 0.025m and distance of the ball is 36cm= 0.36m)

Now putting the given values in the formula -

F_b_i_c_e_p_s\times 0.025= 0.95\times9.8\times\frac{0.36}{2} +1.50\times 0.36

F_b_i_c_e_p_s=218.38N

Now, lets calculate the force exerted by elbow F_e_l_b_o_w -

Balancing the vertical forces

F_b_i_c_e_p_s=F_e_l_b_o_w+w_f+w_b_a_l_l

F_e_l_b_o_w = 218.38-(1.00\times9.8)-(0.95\times9.8)

F_e_l_b_o_w=194.37N

8 0
3 years ago
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