I must assume that you meant the following:
10(Q-3R)
P = ----------------
R
Multiplying both sides by R, we get PR = 10R(Q-3R), or PR = 10RQ - 30R^2.
Rearranging these terms so that powers of R are in descending order:
30R^2 - 10RQ + PR = 0
Factoring out R, we get
R(30R - 10Q + P) = 0. This has two solutions:
R = 0, and 10Q - P
30R = 10Q - P, so that R = --------------
30
Answer:
Step-by-step explanation:
P(rolling 2 or 5)=2/6=1/3
Answer:
![{ \tt{pH = - log[H {}^{ + } ]}} \\ pH = - log(4.2 \times {10}^{ - 5} ) \\ pH = 4.38](https://tex.z-dn.net/?f=%7B%20%5Ctt%7BpH%20%3D%20%20-%20%20log%5BH%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%7D%7D%20%5C%5C%20%20pH%20%3D%20%20-%20%20log%284.2%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20%29%20%20%5C%5C%20pH%20%3D%204.38)
Step-by-step explanation:
H
Answer:
Step-by-step explanation:
Option B is the correct answer
