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irga5000 [103]
3 years ago
13

A cardboard box without a top is to have volume 62500 cubic cm. find the dimensions which minimize the amount of material used.

Mathematics
1 answer:
bezimeni [28]3 years ago
8 0

Answer: A cardboard box without a lid is to have a volume of 32,000 cubic cm. Find the dimensions that minimize the amount of cardboard used

. ans: base 40 x 40, height = 20  

Solution:  

The typical box might look like the one below  

where . In addition we have xyz = 32000 ,so we need to minimize .  

We have,  

 

From the geometry of the problem  so y = x. So  or x = 40.  

Finally, y = x = 40 and z = 32000/(xy)=20.

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Will mark brainliest
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Answer:

Interquartile range => 7

Third quartile => 22

Range => 13

First quartile => 15

Step-by-step explanation:

Order your data set, from the least amount to the highest amount:

$12, $14, $15, $15, $15, $15, $16, $22, $24, $25

Interquartile range (IQR) = third quartile (Q3) - first quartile (Q1)

Q1 = the middle value of the lower part of the data set, from the median to your left.

Q3 = the middle value of the upper part of the data set, from the median to your right.

The median lies between the 5th and 6th value that is enclosed in the parenthesis below:

$12, $14, ($15), $15, $15,[Median], $15, $16, ($22), $24, $25

The median divides the data set into upper and lower part.

Median = \frac{15 + 15}{2} = 15

First quartile: Q1 = $15

Third quartile: Q3 = $22

IQR = $22 - $15 = $7

Range = highest amount - least amount = 25 - 12 = $13

3 0
3 years ago
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yanalaym [24]
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Answer:

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Step-by-step explanation:

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Answer:

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 —————

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Step-by-step explanation:


6 0
3 years ago
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