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vova2212 [387]
1 year ago
9

Which expression is equivalent to \frac{r^9}{r^3}

Mathematics
2 answers:
Aleksandr [31]1 year ago
5 0

Hii!

___________________________________________________________

\rightsquigarrow\circ\boldsymbol{Answer}\circ\leftharpoonup

r^6

\rightsquigarrow\circ\boldsymbol{Explanation}\circ\leftharpoonup

To simplify this we need to use the division property of exponents:

\large\boxed{\mathtt{\frac{x^m}{x^n} =x^{m-n}}}. So if we divide two numbers with the same base, we subtract their exponents.

Let's apply this rule here.

\twoheadrightarrow\sf r^9\div r^3.

\bullet <em>Since these two numbers have the same base, we subtract their exponents</em>

<em />\twoheadrightarrow\sf r^6

\bullet <em>Great job! We found the answer</em>

--

Hope that this helped! Best wishes.

\textsl{Reach far. Aim high. Dream big.}\\\boldsymbol{-Greetings!-}

--

dsp731 year ago
4 0

Answer: \frac{r^9}{r^3} = r^{9-3} = r^6

We subtract the exponents when dividing terms with the same base.

The general rule is \frac{a^b}{a^c} = a^{b-c}

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Find the 2nd Derivative:<br> f(x) = 3x⁴ + 2x² - 8x + 4
ad-work [718]

Answer:

f''(x)=36x^2+4

Step-by-step explanation:

Let's start by finding the first derivative of f(x)= 3x^4+2x^2-8x+4. We can do so by using the power rule for derivatives.

The power rule states that:

  • \frac{d}{dx} (x^n) = n \times x^n^-^1

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

  • \frac{d}{dx} (3x^4+2x^2-8x+4)

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)

Simplify the equation.

  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)
  • \frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)
  • f'(x)=12x^3+4x-8

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).

  • \frac{d}{d} (f'x) = \frac{d}{dx} (12x^3+4x-8)
  • \frac{d}{dx} (12x^3+4x-8) = ((3)12x^3^-^1 + (1)4x^1^-^1 - (0)8)

Simplify the equation.

  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4x^0 - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4(1) - 0)
  • \frac{d}{dx} (12x^3+4x-8) = (36x^2 + 4 )

Therefore, this is the 2nd derivative of the function f(x).

We can say that: f''(x)=36x^2+4

6 0
2 years ago
Read 2 more answers
The 3rd and 6th term of a geometric progression are 9/2 and 243/16 respectively find the first term, common ratio, seventh term​
sashaice [31]

Answer:

Hello,

Step-by-step explanation:

Let\ (u_n)\ the\ geometric\ progression.\\\\r\ is\ the\ common\ ratio.\\\\u_3=u_0*r^3\\u_6=u_0*r^6\\\\\dfrac{u_6}{u_3} =r^3=\dfrac{\frac{243}{16} }{\frac{9}{2} } =\dfrac{27}{8} =(\frac{3}{2} )^3\\\\\boxed{r=\dfrac{3}{2} }\\\\\\u_3=u_1*r^2 \Longrightarrow\ u_1=\dfrac{u_3}{r^2} =\dfrac{\frac{9}{2} }{(\frac{3}{2^2}) } =2\\\\\\u_7=u_6*\dfrac{3}{2} =\dfrac{729}{32}

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lilavasa [31]
Sorry I'm not to sure
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Josue went to his favorite donut shop with his friend. The donut shop was having a special. A dozen donuts was selling $11.76. H
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Answer:

0.98 cents

Step-by-step explanation:

All you do to solve this is ou do 11.76 divided by 12

11.76 divided by 12 is actually just 98 cents (0.98)

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Which property of real numbers is illustrated by the equation 52+(27+35= (52+27) +36?
Wittaler [7]
The answer is b associative property
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