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tekilochka [14]
3 years ago
15

Find y if 1030404(3y+36) = 1030403(3y+36).

Mathematics
1 answer:
Blababa [14]3 years ago
7 0

Answer:

y= - 12

Step-by-step explanation:

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Svetach [21]
The answer would be 7-x.
8 0
3 years ago
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Multiply.
Kamila [148]
Expand the following:
(x - 6) (3 x^2 + 10 x - 1)
Hint: | Multiply out (x - 6) (3 x^2 + 10 x - 1).
 | | | | x | - | 6
 | | 3 x^2 | + | 10 x | - | 1
 | | | | -x | + | 6
 | | 10 x^2 | - | 60 x | + | 0
3 x^3 | - | 18 x^2 | + | 0 x | + | 0
3 x^3 | - | 8 x^2 | - | 61 x | + | 6:
Answer:  3 x^3 - 8 x^2 - 61 x + 6 Thus B:
7 0
3 years ago
Refer to the technology output given to the right that results from measured hemoglobin levels (g/dL) in 100 randomly selected a
charle [14.2K]

Answer:

Step-by-step explanation:

a)

Confidence interval in less than symbol expressed as

\bar{x} - E < \mu < \bar{x} + E&#10;

Where \bar{x} is sample mean and  E is margin of error.

13.03 < \mu 13.42&#10;

b)

The given t interval is (13.032 , 13.418 )&#10;

That is \bar{x} - E = 13.032 and \bar{x} + E = 13.418

Solve these two equation by adding together.

2 \bar{x} = 13.032 + 13.418&#10;\\\\\bar{x} = 13.225

Solve this value of \bar{x} in equation \bar{x} - E = 13.032 and solve for E

13.225 - E = 13.032&#10;\\\\E = 0.193&#10;

Best point estimate of \mu = \bar{x} = 13.225&#10;

Best point estimate of margin of error = 0.193

c)

Since sample size = 100 which is sufficiently large (Greater than 30) , it is no need to confirm that

sample data appear to be form a population with normal distribution.

8 0
3 years ago
Describe the rotation of J
Serga [27]

Answer:

The coordinates of J' when rotating by 90° counterclockwise will be: J'(3, 1)

The coordinates of J' when rotating by 90° clockwise will be: J'(-3, -1)

Step-by-step explanation:

Square JKLM with vertices

  • J(1, -3)
  • K(5, 0)
  • L(8, -4)
  • M(4, -7)

We have to determine the answer for the image J' of the point (1, -3) when we rotate the point by 90° counterclockwise, we need to switch x and y, make y negative.

In other words, the rule to rotate a point by 90° counterclockwise.

P(x, y) → P'(-y, x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(3, 1)

Therefore, the coordinates of J' when rotating by 90° counterclockwise will be:  J'(3, 1).

When the point is rotated by 90° clockwise, we need to switch x and y, make x negative.

In other words, the rule to rotate a point by 90° clockwise.

P(x, y) → P'(y, -x)

As we are given that J(1, -3), so the coordinates of J' will be:

J(1, -3) → J'(-3, -1)

Therefore, the coordinates of J' when rotating by 90° clockwise will be:  J'(-3, -1)

3 0
3 years ago
1 2 4 3 6 8 7 14 16? whats the next term in this sequence?
ANEK [815]
The next term in this sequence would be 18.
8 0
3 years ago
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