Answer:
10.8
Step-by-step explanation:
So, these are actually pretty simple once you learn the equality used to solve for "x" and when to implement this method. You can use this equality to solve for a segment "x" anytime that two secant lines cutting through a circle come from the same point outside the circle.
Secant: by geometric definition is just a straight line that cuts a curve into multiple pieces.
I did one of them for you hopefully you can use my work for "a" to help you solve for "b".
For a. I got x=7.
Answer:
36
Step-by-step explanation:
6 X 6 = 36
<span>y(1) = 0
y'(1) = e
y" = c1ex + c2e-x
y' = c1ex - c2e-x
for solving c1, 0 = c1e1 + c2e-1
this implies that c1 = - (c2/e2) and
to solve c2
e1 = (-c2e-2)e1 - c2e-1
e1 = (-2c2e-1)
c2= - (e1/2e-1) = - (e2/2)
c1 = - (c2/e2) = (e2/2e2)
Therefore y =(e2/2e2)ex - (e2/2)e-x</span>
The answer is
5mn(KUASA DUA) -6gh(KUASA DUA) +2