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larisa86 [58]
2 years ago
10

What is the expression for this verbal description?a. six times a number less nine​

Mathematics
1 answer:
Andrews [41]2 years ago
3 0


three times a number and five" translates to "3x + 5," while the phrase "three times the sum of a ... The total of six and some number. 6 + x ... The difference of a number and three. X – 3 less. Nine less a number. 9 – X.
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What is the square root of 30 rounded to the 2 decimal places.
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Answer:

5.48 or 5.477225575 hope this helps

Step-by-step explanation:

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Karen is buying pens and pencils for the new school year. She wants to have no more than 25 writing utensils in all. She also wa
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For this case, the first thing we must do is define variables.
 We have then:
 x: number of pens
 y: number of pencils
 We now write the system of inequations:
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y  \geq  (x - 3) ^ 2

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3 years ago
❊ Simplify :
DiKsa [7]

Answer:

See Below.

Step-by-step explanation:

Problem 1)

We want to simplify:

\displaystyle \frac{a+2}{a^2+a-2}+\frac{3}{a^2-1}

First, let's factor the denominators of each term. For the second term, we can use the difference of two squares. Hence:

\displaystyle =\frac{a+2}{(a+2)(a-1)}+\frac{3}{(a+1)(a-1)}

Now, create a common denominator. To do this, we can multiply the first term by (<em>a</em> + 1) and the second term by (<em>a</em> + 2). Hence:

\displaystyle =\frac{(a+2)(a+1)}{(a+2)(a-1)(a+1)}+\frac{3(a+2)}{(a+2)(a-1)(a+1)}

Add the fractions:

\displaystyle =\frac{(a+2)(a+1)+3(a+2)}{(a+2)(a-1)(a+1)}

Factor:

\displaystyle =\frac{(a+2)((a+1)+3)}{(a+2)(a-1)(a+1)}

Simplify:

\displaystyle =\frac{a+4}{(a-1)(a+1)}

We can expand. Therefore:

\displaystyle =\frac{a+4}{a^2-1}

Problem 2)

We want to simplify:

\displaystyle \frac{1}{(a-b)(b-c)}+\frac{1}{(c-b)(a-c)}

Again, let's create a common denominator. First, let's factor out a negative from the second term:

\displaystyle \begin{aligned} \displaystyle &= \frac{1}{(a-b)(b-c)}+\frac{1}{(-(b-c))(a-c)}\\\\&=\displaystyle \frac{1}{(a-b)(b-c)}-\frac{1}{(b-c)(a-c)}\\\end{aligned}

Now to create a common denominator, we can multiply the first term by (<em>a</em> - <em>c</em>) and the second term by (<em>a</em> - <em>b</em>). Hence:

\displaystyle =\frac{(a-c)}{(a-b)(b-c)(a-c)}-\frac{(a-b)}{(a-b)(b-c)(a-c)}

Subtract the fractions:

\displaystyle =\frac{(a-c)-(a-b)}{(a-b)(b-c)(a-c)}

Distribute and simplify:

\displaystyle =\frac{a-c-a+b}{(a-b)(b-c)(a-c)}=\frac{b-c}{(a-b)(b-c)(a-c)}

Cancel. Hence:

\displaystyle =\frac{1}{(a-b)(a-c)}

4 0
3 years ago
What is the solution to the inequality -3x - 42 &gt; 3
rosijanka [135]

Answer:

I don’t know which answer choice it is since C and D are the same but the answer is supposed to be x < -15.

Step-by-step explanation:

the image has the work shown

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Answer:4/13

Step-by-step explanation:

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2 years ago
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