CD:2 at $16.99 each=$33.98
DVD:1 at $36.29
$33.98+$36.29=
$70.27
6.75%*70.27=4.743225
round to the nearest tenth:
4.74
Andrian will pay
<u>$4.74 as sales tax </u>
Answer:
-4
Step-by-step explanation:
The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.
We need the answer in cubic centimeters. So let's convert 350 cubic inches to cubic centimeters. We will do it unit conversion way (the long way).
We will write cubic inches as three inches side-by-side
350 in^3
<h3>What is the ratio of the centimeter?</h3>
This way, we can multiply this by the ratio of centimeters to inches [2.54 cm = 1 inch], so that the units cancel and we have cubic centimeters (what we desire).
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in
So, we can cancel the three inches top and bottom thus we have the answer in centimeters cubed. And the value is
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in.
350 in^3*3.54cm/1in*3.54cm/1in*3.54cm/1in=5735.47.
So 350 cubic inches is approximately 5735.5 cubic centimeters (rounded to 1 decimal place).
This is larger than a 5500 cubic centimeters engine.
5735.5-5500=235.5cubic centimeters.
The bigger engine is about 235.5 cubic centimeters larger than the smaller engine.
To learn more about the significant figures visit:
brainly.com/question/24491627
#SPJ1
Answer:
2x^3+12x^2+10x-24
Step-by-step explanation:
(2x^2+6x-8)(x+3)
2x^3+6x^2-8x+6x^2+18x-24
2x^3+6x^2+6x^2-8x+18x-24
2x^3+12x^2+10x-24
You can use systems of equations for this one.
We are going to use 'q' as the number of quarters Rafael had,
and 'n' as the number of nickels Rafael had.
You can write the first equation like this:
3.50=0.05n+0.25q
This says that however many 5 cent nickels he had, and however many
25 cent quarters he had, all added up to value $3.50.
Our second equation is this:
q=n+8
This says that Rafael had 8 more nickels that he had quarters.
We can now use substitution to solve our system.
We can rewrite our first equation from:
3.50=0.05n+0.25q
to:
3.50=0.05n+0.25(n+8)
From here, simply solve using PEMDAS.
3.50=0.05n+0.25(n+8) --Distribute 0.25 to the n and the 8
3.50=0.05n+0.25n+2 --Subtract 2 from both sides
1.50=0.05n+0.25n --Combine like terms
1.50=0.30n --Divide both sides by 0.30
5=n --This is how many NICKELS Rafael has.
We now know how many nickels he has, but the question is asking us
how many quarters he has.
Simply substitute our now-known value of n into either of our previous
equations (3.50=0.05n+0.25q or q=n+8) and solve.
We now know that Rafael had 13 quarters.
To check, just substitute our known values for our variables and solve.
If both sides of our equations are equal, then you know that you have
yourself a correct answer.
Happy math-ing :)
