Answer:5/3
Step-by-step explanation:
first u need to change is mixed fraction in to normal fraction
3 1/3-5
3 1/3 means 3*3+1 =10
therefor 10/3-5
u need to find the lcm or the common for the two factor (3 and 1 )
the lcm is 3
so 10-5/3 =5/3
When we are given a line cutting diagonally from one corner of a rectangle to the opposite corner, we are given two triangles.
300ft
____
| /|
| / |
| / |
| / |400ft
| / |
| / |
|/ |
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*not to scale
Now, using the right-angle trigonometry rule, we can find the hypotenuse (the diagonal line) which represents the footpath.
a^2 + b^2 = c^2
{where a is one side length, b is another side length, and c is the hypotenuse}
Thus, we make c the subject of the equation and substitute the other known values:
c^2 = 400^2 + 300^2
= 160,000 + 90,000
= 250,000
Now we move the 'squared' (^2) from the left hand side to the right hand side. When moving it across the equal sign (=) the result becomes the 'root' of itself:
c = _/250,000
= 500
Therefore, the length of the diagonal path is 500ft.
Answer:
2
Step-by-step explanation:
example A(2a,0),B(2b,0)
C(2b,2c),D(2a,2c)
mid point of AC=((2a+2b)/2,(0+2c)/2)=(a+b,c)
mid point of BD=((2b+2a)/2,(0+2c)/2)=(a+b,c)
∴midpoint of diagonals same or diagonals bisect each other.
<em>Greetings from Brasil...</em>
According to the statement of the question, we can assemble the following system of equation:
X · Y = - 2 i
X + Y = 7 ii
isolating X from i and replacing in ii:
X · Y = - 2
X = - 2/Y
X + Y = 7
(- 2/Y) + Y = 7 <em>multiplying everything by Y</em>
(- 2Y/Y) + Y·Y = 7·Y
- 2 + Y² = 7X <em> rearranging everything</em>
Y² - 7X - 2 = 0 <em>2nd degree equation</em>
Δ = b² - 4·a·c
Δ = (- 7)² - 4·1·(- 2)
Δ = 49 + 8
Δ = 57
X = (- b ± √Δ)/2a
X' = (- (- 7) ± √57)/2·1
X' = (7 + √57)/2
X' = (7 - √57)/2
So, the numbers are:
<h2>
(7 + √57)/2</h2>
and
<h2>
(7 - √57)/2</h2>
