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2 years ago

5

The length of one leg of a right triangle is 9cm and 40cm

2 answers:

Vika [28.1K]2 years ago

5 0

Answer:

B. 41

Step-by-step explanation:

Missing sides of a right triangle can be found using the Pythagorean Theorem. The formula for the Pythagorean Theorem is: a² + b² = c², where 'a' and 'b' represent the legs of the triangle and 'c' represents the hypotenuse. Since the leg lengths of the right triangle are given as 9cm and 40cm, we can set up the following equation:

9² + 40² = c² or 81 + 1600 = c²

1681 = c²

Take the square root of both sides: √1681 = √c²

c = 41 (answer choice B)

Damm [24]2 years ago

4 0

Answer:

Step-by-step explanation:

I think ur is D but I'm not sure

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Find the slope from the given equation. 9y = -3x + 5

anygoal [31]

Answer:

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Step-by-step explanation:

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sasho [114]

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Solve for x. Round to the nearest hundredth.

zlopas [31]

<u>Given </u>that the length of the hypotenuse is 8 and the angle is 42°

The length of the one leg of the triangle is x.

We need to determine the value of x.

<u>Value of x:</u>

The value of x can be determined using the trigonometric ratio.

Thus, we have;

$sin \ \theta=\frac{opp}{hyp}$

Substituting the values, we get;

$sin \ 42^{\circ}=\frac{x}{8}$

Multiplying both sides of the equation by 8, we get;

$sin \ 42^{\circ}\times8=x$

Simplifying, we get;

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3 years ago

Find the ratio of:<br> (a) 5 km to 400 m<br> (b) 2 hours to 160 minutes

aleksandr82 [10.1K]

Answer:

Answer - a) 1:80

b) 1:80

Step-by-step explanation:

All the ratio should be written in lowest form. these are the answers for both the questions.

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1) State the amplitude, period, phase shift, vertical shift and graph

bogdanovich [222]

Answer:

See answers and explanations below (along with a visual graph)

Step-by-step explanation:

For the function $y=acos(b(x+c))+d$ :

Amplitude: $|a|$

Period: $\frac{2\pi}{|b|}$

Phase shift: $\frac{-c}{b}$

Vertical shift: $d$

Therefore, for $y=2cos(\frac{2}{3}(\theta+\pi))-1$ :

Amplitude: $|a|=|2|=2$ , which is 2 units above and below the midline (see d)

Period: $\frac{2\pi}{|b|}=\frac{2\pi}{|\frac{2}{3}|}=\frac{2\pi}{\frac{2}{3}}=3\pi$ , so the cycle will repeat every 3π units

Phase shift: $\frac{-c}{b}=\frac{-\frac{2\pi}{3} }{\frac{2}{3} }=-\pi$ , or π units to the left

Vertical shift: $d=-1$ , or 1 unit down

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2 years ago