The equation is already solved for the variable t To solve for any other variable simply rearrange theequation to have the indicated variable on one sideof the equals sign and everything else on the other. For example, to solve for a: t=an+b subtract b from both sidest-b = an divide both sides by n(t-b)/n = a Or: a = (t-b)/n Work in the same manner to solve for either b or n: b = t-an n = (t-b)/a
Step-by-step explanation:
Use the formula (Y2 - Y1)/(X2 - X1) to find the slope between two points
We'll make Point 1 (which is X1 and Y1) the Y-intercept so
X1, Y1 = (0, 5.00)
And we'll make Point 2 (which is X2 and Y2) the point on the trend line
X2, Y2 = (200, 6.00)
Plug into the formula:
(6.00 - 5.00)/(200 - 0)
= 1/200 or 0.005
Slope: 1/200 or 0.005
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As C is the mid-point of BD.
Therefore, BC=DC ...(i)
As AB ⊥ BD and ED ⊥ BD
So, ∠ABC= 90° and ∠EDC= 90°
Therefore, ∠ABC=∠EDC= 90° ...(ii)
As two line segments, AE and BD intersect at point C, so the vertically opposite angles are equal.
Therefore, ∠BCA=∠DCE ...(iii)
Now, in ΔABC and ΔEDC,
Angle, ∠BCA=∠DCE [ from equation (iii)]
Side, BC=DC [ from equation (i)]
Angle, ∠ABC=∠EDC [ from equation (ii)]
So, by ASA property of congruency, ΔABC and ΔEDC are congruent
Hence, ΔABC ≅ ΔEDC.
There’s 11 I believe I might not be right
Answer:
cos(F) = 9/41
Step-by-step explanation:
The triangles are similar, so you know that ...
... cos(D) = cos(A) = 40/41.
From trig relations, you know ...
... cos(F) = sin(D)
and
... sin(D)² +cos(D)² = 1
So ...
... cos(F) = sin(D) = √(1 -cos(D)²) = √(1 -(40/41)²) = √(81/1681)
... cos(F) = 9/41
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The ratio for cos(A) tells you that you can consider AB=40, AC=41. Then, using the Pythagorean theorem, you can find BC = √(41² -40²) = √81 = 9.
From the definition of the cosine, you know cos(C) = BC/AC = 9/41. Because the triangles are similar, you know
... cos(F) = cos(C) = 9/41