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serious [3.7K]
3 years ago
12

I need help with these three questions

Mathematics
1 answer:
dusya [7]3 years ago
3 0
0.55 per pound
90 miles per day
16 oz for 3.19
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if a runner finishes the 26.2. mille race in 4 hours and 37 mins and Wilson kipping finish in 4 minutes and 43 seconds per mile
Neporo4naja [7]

Answer

a) Wilson Kipsang is 7.046 miles per hour faster than the average runner.

Solution is presented below under Explanation.

b) Wilson Kipsang is 2.24 times faster than the average runner.

c) When the average runner is at mile 6, Kipsang will be at mile 13.45.

d) Kipsang's record time = 2 hours, 3 minutes, 34.6 seconds

Explanation

To solve this, we will calculate the speed of the average runner and then the speed of Wilson Kipsang

Speed = (Distance/Time)

For the average runner

Distance = 26.2 miles

Time = 4 hours 37 mins = 4 hours + (37/60) = 4.617 hours

Speed = (Distance/Time)

Speed = (26.2/4.617)

Speed = 5.675 miles per hour

For Wilson Kipsang

Distance = 1 mile

Time = 4 minutes 43 seconds = (4/60) + (43/3600) = 0.0667 + 0.01194 = 0.0786 hour

Speed = (Distance/Time)

Speed = (1/0.0786) = 12.721 miles per hour

So, now, we are asked to find how much faster than the average runner is Wilson Kipsang

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

Wilson Kipsang is faster than the average runner by

(12.721 - 5.676) = 7.046 miles per hour

b) We are asked to find how many times faster than the average runner Wilson Kipsang is.

Let the number of times he is faster than the average runner be x

Wilson Kipsang's speed = 12.721 miles per hour

Average runner's speed = 5.675 miles per hour

(5.675) (x) = (12.721)

Divide both sides by 5.675

x = (12.721/5.675)

x = 2.24 times

c) If the average runner is at mile 6, where would Kipsang be?

To do this, we will find the time it takes the average runner to be at mile 6, then use that time to find where Kipsang would be.

Speed = (Distance/Time)

By cross multiplying, we see that

Time = (Distance/Speed)

For the average runner

Distance = 6 miles

Speed = 5.675 miles per hour

Time = (Distance/Speed)

Time = (6/5.675) = 1.057 hours

For Wilson Kipsang,

Speed = (Distance/Time)

By cross multiplying

Distance = (Speed) (Time)

Speed = 12.721 miles per hour

Time = 1.057 hours

Distance = (Speed) (Time)

Distance = (12.721) (1.057)

Distance = 13.45 miles

d) We were told that for Kipsang

1 mile = 4 minutes 43 seconds

26.2 miles = 26.2 (4 minutes 43 seconds)

26.2 miles = 26.2 (283 seconds) = 7414.6 seconds

We can then convert this further

7414.6 seconds = 2 hours, 3 minutes, 34.6 seconds

Hope this Helps!!!

4 0
1 year ago
Find the slope of the line that contains the points (6,3) and (12,0).
777dan777 [17]
M= y2-y1/x2-x1
3-0/6-12= 3/-6= -1/2
(Slope) m=-1/2
6 0
3 years ago
Read 2 more answers
Determine the slope of the line?​
antoniya [11.8K]

Answer:

C

Step-by-step explanation:

m=rise/run

rise is 1

run is 4

1/4=0.25

hope this helps :3

if it did pls mark as brainliest

3 0
3 years ago
Whats the surgace area for this??? answers to all 9f tgese please
vlada-n [284]

2(6*8)=96

2(6*3)=36

2(8*3)=48

96+36+48= 180 sq. in.

(The above is the answer to #2).I shouldn't give the answer to all of them, but I can explain how to do it. In order to calculate surface area, you need to find the area for all sides of the shape. For example, #2 has six sides, so you need to find the area for all six of those sides. There are two sides that are 8 x 3, two sides that are 6 x 8, and two sides that are 6 x 3. Therefore, your equation would be 2(8x3) + 2(6x3) + 2(6x8). From that you get 48+36+96 = 180 square inches (sq. in.)

4 0
3 years ago
What is the m ZACB?<br> 10°<br> 50°<br> 90°<br> 180°
kifflom [539]

Answer:

50 deg

Step-by-step explanation:

In an right triangle, the acute angles are complementary. That means their measures have a sum of 90 deg.

m<C + m<B = 90

7x - 20 + 4x = 90

11x = 110

x = 10

m<ACB= 7x - 20

m<ACB = 7(10) - 20

m<ACB = 70 - 20

m<ACB = 50

Answer: m<ACB = 50 deg

7 0
3 years ago
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