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2 years ago

Select the correct answer.

Mathematics

2 answers:

lakkis [162]2 years ago

8 0

Answer:

6x + 4y ≤ 50

x + y ≥ 10

Step-by-step explanation:

$6 is the cost of stuffed animals $4 is the cost of toy trucks and the her maximum budget is $50 it would be 6x+4y is less then or equal to 50 and there is AT LEAST 10 people so the amounts which are x and y would be equal to or greater than 10.

olga2289 [7]2 years ago

8 0

Answer:

$6x+4y\leq 50$

$x+y\geq 10$

Step-by-step explanation:

$x$ represents the number of stuffed animals.

$y$ represents the number of toy trucks.

Now, according to the problem, she found stuffed animals for $6.00 each and toy trucks for $4.00 each. Also, Laura has a restricted budget of $50. All these can be expressde as

$6x+4y\leq 50$

Also, the problem states that Laura wants to provide one partu favor per person to at least 10 people, that means

$x+y\geq 10$ , because "at least" represents a minimum value, which is expressed with $\geq$ .

Therefore, the inequality system that models this situation is

$6x+4y\leq 50$

$x+y\geq 10$

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Jack and Jill live 126 km apart. They want to leave their homes at the same time,

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Answer:

Both will leave their homes to meet on time at 9 am

Step-by-step explanation:

Given as, Distance between Jack and Jill = 126 km

Speed of Jack rides = 18 kilometers per hours

Speed of Jill rides = 24 kilometers per hours

Let the distance travel by Jack = x km

And the distance travel by Jill = (126 - x ) km

Time taken by Jack and Jill = T hours

Now , Distance = Speed × Time

So, x = 18 × T

And 126 - x = 24 × T

Or, 126 - x = 24 × $\frac{x}{18}$

Or, 126 - x = x × $\frac{4}{3}$

Or, 378 - 3x = 4x

Or, 378 = 7x

i.e x = $\frac{378}{7}$ = 54 km

And distance travel by Jill = 126 - 54 = 72 km

So, time taken by Jack = $\frac{x}{18}$ = $\frac{54}{18}$

Or, Time taken by Jack = 3 hours

Similarly Time take by Jill = $\frac{72}{24}$ = 3 hours

∵ Both Jack and Jill will take 3 hours to meet at 12 : 00 pm

Hence, Both will leave their homes to meet on time at 9 am Answer

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Answer:

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Step-by-step explanation:

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To raise money for a class trip, students sold bags of mixed nuts and bags of dried fruit. Evan sold 12 bags of mixed nuts and 1

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12 bags of mixed nuts for R2 each and 10 bags of dried fruit for R3 each

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PROBLEM 2 The height of a golf ball in feet can be determined using the formula h(t) = -16t2 + 100x , where t is the number of s

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Answer:

Step-by-step explanation:

Given the height of a golf ball in feet modelled by the formula h(t) = -16t² + 100x where t is in seconds, we are to find the height of the golf after 2.5 seconds. To do that we will simply substitute t = 2.5secs into the formula given;

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3 years ago

A recipe submitted to a magazine by one of its subscribers’ states that the mean baking time for a cheesecake is 55 minutes. A t

EastWind [94]

Answer:

$t=\frac{59.4-55}{\frac{3.239}{\sqrt{10}}}=4.296$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =P(t_{(9)}>4.296)=0.001$

And for this case the p value is lower than the significance level so we have enough evidence to reject the null hypothesis and then we can conclude that true mean is higher than 55.

Step-by-step explanation:

Information given

We have the following data: 54 55 58 59 59 60 61 61 62 65

The sample mean and deviation can be calculated with the following formulas:

$\bar X = \frac{\sum_{i=1}^n X_i}{n}$

$s=\sqrt{\frac{\sum_{i=1}^n (X-i -\bar x)^2}{n-1}}$

$\bar X=59.4$ represent the sample mean

$s=3.239$ represent the sample standard deviation

$n=10$ sample size

$\alpha=0.05$ represent the significance level

t would represent the statistic

$p_v$ represent the p value

System of hypothesis

We want to test if the true mean is higher than 55, the system of hypothesis would be:

Null hypothesis: $\mu \leq 55$

Alternative hypothesis: $\mu > 55$

Replacing the info given we got:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

And replacing the info given we got:

$t=\frac{59.4-55}{\frac{3.239}{\sqrt{10}}}=4.296$

The degrees of freedom are given by:

$df=n-1=10-1=9$

The p value for this case is given by:

$p_v =P(t_{(9)}>4.296)=0.001$

And for this case the p value is lower than the significance level so we have enough evidence to reject the null hypothesis and then we can conclude that true mean is higher than 55

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