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3 years ago

Select the correct answer.

Mathematics

2 answers:

lakkis [162]3 years ago

8 0

Answer:

6x + 4y ≤ 50

x + y ≥ 10

Step-by-step explanation:

$6 is the cost of stuffed animals $4 is the cost of toy trucks and the her maximum budget is $50 it would be 6x+4y is less then or equal to 50 and there is AT LEAST 10 people so the amounts which are x and y would be equal to or greater than 10.

olga2289 [7]3 years ago

8 0

Answer:

$6x+4y\leq 50$

$x+y\geq 10$

Step-by-step explanation:

$x$ represents the number of stuffed animals.

$y$ represents the number of toy trucks.

Now, according to the problem, she found stuffed animals for $6.00 each and toy trucks for $4.00 each. Also, Laura has a restricted budget of $50. All these can be expressde as

$6x+4y\leq 50$

Also, the problem states that Laura wants to provide one partu favor per person to at least 10 people, that means

$x+y\geq 10$ , because "at least" represents a minimum value, which is expressed with $\geq$ .

Therefore, the inequality system that models this situation is

$6x+4y\leq 50$

$x+y\geq 10$

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How many solutions does this system have? y=3/4x-5 -3x+4y=-20?

Komok [63]

4y=-20+3x and 4y=13.6x-20
so
-20+3x=13.6x-20
3x=13.6x
3=13.6 so it is wrong and system doesn’t have solution

4 0

3 years ago

Prove that the roots of x2+(1-k)x+k-3=0 are real for all real values of k

masha68 [24]

Answer:

Roots are not real

Step-by-step explanation:

To prove : The roots of x^2 +(1-k)x+k-3=0x

+(1−k)x+k−3=0 are real for all real values of k ?

Solution :

The roots are real when discriminant is greater than equal to zero.

i.e. b^2-4ac\geq 0b

−4ac≥0

The quadratic equation x^2 +(1-k)x+k-3=0x

+(1−k)x+k−3=0

Here, a=1, b=1-k and c=k-3

Substitute the values,

We find the discriminant,

D=(1-k)^2-4(1)(k-3)D=(1−k)

−4(1)(k−3)

D=1+k^2-2k-4k+12D=1+k

−2k−4k+12

D=k^2-6k+13D=k

−6k+13

D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))

For roots to be real, D ≥ 0

But the roots are imaginary therefore the roots of the given equation are not real for any value of k.

6 0

3 years ago

A random sample is selected from a normally distributed population. The following sample statistics are obtained: n = 20, = 30,

Flura [38]

Answer:

b) The margin of error is approximately 3.24

e) The critical value is 1.7921.

Step-by-step explanation:

Step(i):-

Given sample size 'n' =20

Given sample standard deviation 's' = 10

 Margin of error 

The margin of error is determined by

 $M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }$ 

The level of significance ∝ =0.95

The degrees of freedom = n-1 = 20-1=19

t₀.₉₅ = 1.729

$M.E = \frac{1.729 X10 }{\sqrt{20} }$

Margin of error = 3.866

Step(ii):-

 Margin of error 

The margin of error is determined by

 $M.E = \frac{t_{\alpha } S.D }{\sqrt{n} }$ 

Given another sample size n =30

The level of significance ∝ =0.95

The degrees of freedom = n-1 = 30-1=29

t₀.₉₅ = 1.70

$M.E = \frac{1.7021 X10 }{\sqrt{30} } =3.24$

Margin of error = 3.24

5 0

3 years ago

Q2: One end of a cable is attached to the top of a flagpole and the other end is attached 6 feet away from the base of

Bumek [7]

Answer:

13.4 feet

Step-by-step explanation:

a²+b²=c²

12²+6²=c²

144+36= $\sqrt{180}$

=13.4

7 0

3 years ago

If 7(p+3)= -28 then what does p equal

Ratling [72]

Answer:

p = -7

Step-by-step explanation:

7(p+3) = -28

now we times the inside of the parenthese by 7

7p+21 =-28

now we minus 21 on both sides

7p= -49

now divide

p = - 7

4 0

3 years ago

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