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3 years ago

Select the correct answer.

Mathematics

2 answers:

lakkis [162]3 years ago

8 0

Answer:

6x + 4y ≤ 50

x + y ≥ 10

Step-by-step explanation:

$6 is the cost of stuffed animals $4 is the cost of toy trucks and the her maximum budget is $50 it would be 6x+4y is less then or equal to 50 and there is AT LEAST 10 people so the amounts which are x and y would be equal to or greater than 10.

olga2289 [7]3 years ago

8 0

Answer:

$6x+4y\leq 50$

$x+y\geq 10$

Step-by-step explanation:

$x$ represents the number of stuffed animals.

$y$ represents the number of toy trucks.

Now, according to the problem, she found stuffed animals for $6.00 each and toy trucks for $4.00 each. Also, Laura has a restricted budget of $50. All these can be expressde as

$6x+4y\leq 50$

Also, the problem states that Laura wants to provide one partu favor per person to at least 10 people, that means

$x+y\geq 10$ , because "at least" represents a minimum value, which is expressed with $\geq$ .

Therefore, the inequality system that models this situation is

$6x+4y\leq 50$

$x+y\geq 10$

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GREYUIT [131]

Answer:

10 times 2x = 30

Step-by-step explanation:

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3 years ago

Polygon ABCD has the following vertices: A(−3, 3), B(5, 5), C(5, −4), and D(−3, −4) Calculate the area of the polygon.

aniked [119]

To solve this problem you must apply the proccedure shown below:

1. When you plot the given points, you obtain a trapezoid, therefore, you must apply the formula for calculate the area of a trapezoid, which is:

$A=\frac{(B+b)h}{2}$

Where $B$ is the larger base, $b$ is the smaller base and $h$ is the height.

2. The dimensions are:

$B=9units\\ b=7units\\ h=8units$

3. Substitute values:

$\\A=\frac{(9 units+7units)(8units)}{2} A=64 units^{2}$

The answer is: $64 units^{2}$

6 0

3 years ago

Read 2 more answers

Determine whether a figure with the given vertices is a parallelogram. Use the method indicated.

aliya0001 [1]

Answer with explanation:

The coordinates of four points of Quadrilateral ABCD are

A(4, 5), B(–7, –10), C(–4, –9), D(7, 6)

$AB=\sqrt{(4+7)^2+(5+10)^2}\\\\AB=\sqrt{121+225}\\\\AB=\sqrt{346}\\\\BC=\sqrt{(-7+4)^2+(-10+9)^2}\\\\BC=\sqrt{9+1}\\\\BC=\sqrt{10}\\\\CD=\sqrt{(4+7)^2+(5+10)^2}\\\\CD=\sqrt{121+225}\\\\CD=\sqrt{346}\\\\DA=\sqrt{(7-4)^2+(6-5)^2}\\\\DA=\sqrt{9+1}\\\\DA=\sqrt{10}$

Slope between two points is given by

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\m_{1}=\frac{-10-5}{-7-4}\\\\=\frac{-15}{-11}\\\\m_{1}=\frac{15}{11}\\\\m_{2}=\frac{-9+10}{-4+7}\\\\m_{2}=\frac{1}{3}\\\\m_{3}=\frac{6+9}{7+4}\\\\m_{3}=\frac{15}{11}\\\\m_{4}=\frac{6-5}{7-4}\\\\m_{4}=\frac{1}{3}$