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blagie [28]
3 years ago
8

The percent equivalent of 1.09 is ________ and the fraction is ______________

Mathematics
1 answer:
lisov135 [29]3 years ago
6 0
1.09=109% 109\100 the first one is the percent and the second one is the fraction I really hope this helps
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Rama09 [41]

11.6, if you need a decimal. it's in between 11 and 12

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3 years ago
In the image, point A is the center of the circle. Which two line segments must be equal in length?
alex41 [277]
The answer is C (EF and HI)

This is because both lines pass through the centre A, meaning both are diameters. Hence, they are equal in length.
6 0
3 years ago
There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=
yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = \frac{12P4}{12^{4} }

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = \frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }

P(X=2) = 0.401

P(X=3) = \frac{4C3 * 12P2}{12^{4} }

P(x=3) = 0.025

P(X=4) = \frac{12}{12^{4} }

P(X=4) = 0.001

Mean, \mu = \sum xP(x)

\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879

Standard deviation, SD = \sqrt{\sum x^{2} P(x) - \mu^{2}}  \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2}  * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}

SD = 1.033

4 0
4 years ago
2[5x+3]-2=14 what are the solutions
sertanlavr [38]
The answer for this problem is x=1
4 0
3 years ago
What is the volume of this aquarium?
geniusboy [140]

Answer:

2,973 in^3

Step-by-step explanation:

3000- large section

27- smaller center cut-out

6 0
3 years ago
Read 2 more answers
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