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algol [13]
2 years ago
7

Jennifer invested $400 at 6% interest compounded continuously. Write a model m(t) that represents the money in Jennifer's accoun

t in t years. A. B. How much money is in Jennifer's account after 5 years? Round to the nearest cent. C. Approximately when will Jennifer have $800 in her account? Round to the nearest tenth of a year.
Mathematics
1 answer:
ra1l [238]2 years ago
7 0

Answer:

11.5 years

Step-by-step explanation:

Given data

Principal= $400

Rate= 6%

For the compound interest at time t, the expression is given as

A= P(1+r)^t

Substitute

A= 400(1+0.06)^t

A=400(1.06)^t

B. How much money is in Jennifer's account after 5 years

put t= 5

A=400(1.06)^5

A=400*1.338

A=$535.2

C. Approximately when will Jennifer have $800 in her account

A=$800

P=$400

r=6%

t= ln(A/P)/r

t= ln(800/400)/0.06

t= ln(2)/0.06

t= 0.6931/0.06

t=11.551

Hence the time is about 11.5 years

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Answer:

The correct answer will be "0.756596 m²".

Step-by-step explanation:

The given values are:

The radius of an umbrella,

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The height of an umbrella,

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As we know,

The lateral surface of an umbrella will be:

⇒  \pi r\sqrt{r^2+h^2}

On substituting the values, we get

⇒  \pi \times 0.4\sqrt{(0.4)^2=(0.45)^2}

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Step-by-step explanation:

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3 years ago
The ratio (by volume) of salt and sugar in a certain mixture is 4 to 8. If the total volume of the solution is 300 cubic feet, w
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A forester studying the effects of fertilization on certain pine forests in the Southeast is interested in estimating the averag
ahrayia [7]

Answer:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(ZStep-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

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X \sim N(M,4)  

Where \mu=M and \sigma=4

We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

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And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(Z

8 0
3 years ago
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