Question

What is the range of function of y-1=(x+3)^2

Answer 1

$The\ vertex\ form\ of\ a\ quadratic\ function:y=a(x-h)^2+k\\\\where\ (h;\ k)-the\ vertex\\---------------------------\\\\y-1=(x+3)^2\ \ \ \ |add\ 1\ to\ both\ sides\\\\y=(x+3)^2+1\\\\a=1;\ h=-3;\ k=1\\\\a=1 > 0\ therefore\ parabola\ op ens\ upward\\\\vertex\ (-3;\ 1)\\\\therefore\ the\ range\ of\ this\ function\ is\ equal\ [1;\ \infty)\\\\graph\ on\ the\ picture.$