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Ivanshal [37]
3 years ago
5

7 inches, and one of the legs is inches. Find the length of the other leg.

Mathematics
1 answer:
ankoles [38]3 years ago
5 0
Is it a chair? if so it's 7
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A building has an entry the shape of a parabolic arch 84 ft high and 42 ft wide at the base, as shown below. A parabola opening
lara [203]

Answer:

Step-by-step explanation:

Because of the nature of the information we are given, we have no choice but to use the equation

y=a(x-h)^2+k

and solve for a.

We know by the info that the vertex is (0, 84). We also know that if the vertex is at the origin, and that the base is 42 feet wide, it spans 21 feet to the right of the origin and 21 feet to the left of the origin. That means that we have 2 coordinates from which we need to pick one for our x and y in the equation. I don't like negatives, so I am going to choose the coordinate (21, 0) as x and y. Because this parabola opens upside down, as archways of door openings do, our "a" value better come out algebraically as a negative. Let's see...From the vertex we have that h = 0 and k = 84. So filling in:

0=a(21-0)^2+84 and simplifying a bit:

0 = 441a + 84 and

-84 = 441a so

a=-\frac{84}{441}=-\frac{4}{21} Good, a is negative. Your equation is, then:

y=-\frac{4}{21}x^2+84

3 0
3 years ago
Read 2 more answers
Evaluate<br> 4(x+3)(x+1)/(x+5)(x-5) x=3
Aleks04 [339]

Answer:

below

Step-by-step explanation:

4(3 + 1)(3 + 3)(3 + 5)(3 - 5)

4(4)(6)(8)(-2)

16(-96)= -1536

6 0
3 years ago
Which expression is equivalent to-2-7? Subraction with Intergers
vlada-n [284]

Answer:

-7-2

Step-by-step explanation:

5 0
3 years ago
My Notes A street light is mounted at the top of a 15-ft-tall pole. A man 6 ft tall walks away from the pole with a speed of 4 f
Sergio [31]

Answer:

6.667 ft/s

Step-by-step explanation:

Given

Height of street light = 15ft

Height of man = 6ft

Speed away from pole = 4ft/s

Let x represents the distance between the man and the pole, and Let y represents the distance between the tip of the man's shadow to the pole.

This forms a similar triangle (see attachment below).

From similar triangles, we have

(y - x)/6 = y/15 ----- Solve equation

15(y - x) = 6 * y

15y - 15x = 6y ---- Collect Like Terms

15y - 6y = 15x

9y = 15x --- divide through by 9

y = 15x/9

y = 5x/3 ---- differentiate with respect to time, t

dy/dt = 5/3 dx/dt

dx/dt represents rate of change of distance per time = 4ft/s

while dy/dt represents rate of movement of his shadow tips

dy/dt = 5/3 * 4

dy/dt = 20/3 = 6.667 ft/s

4 0
3 years ago
Read 2 more answers
Let
kramer

I think when you copied and pasted your question it re arranged itself

3 0
2 years ago
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