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GaryK [48]
3 years ago
11

Help my dudes its a photooooooooo

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0

Answer: It would be option B (13 over 5).

Step-by-step explanation: Step 1) Subtract 15 from both sides, 5x=13. Step 2) Divide both sides by 5, x=13 over 5. Hope this helps bub <3

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I really need your help
nata0808 [166]

Answer: The median is 30.

1.) Line up each number in numerical order based on the data set.

- 27, 28, 28, 29, 29, 29, 30, 30, 30, 31, 31, 31, 33, 34.

2.) Cross out the numbers from inside out. (Find the middle number.)

- Because the data set has an even amount of numbers, you are left with 2 middle numbers. (30 & 30)

- In this case, you add the numbers together (30 + 30) and divide them by 2. (60/2)

- You end with the result of 30, therefore your answer (the median) is 30.

4 0
3 years ago
Five fourths of a right angle
Lelechka [254]
Five fourths of a right angle

A right angle is 90 degrees.

Five fourths is \sf \frac{5}{4}

Five fourths OF A right triangle

\sf \frac{5}{4} OF 90 degrees

Of means multiplication so:

\sf \frac{5}{4}\times 90

And that equals to 112.5

So your final answer is

\boxed{\bf{112.5~degrees}}
4 0
3 years ago
Can you help me with this
Molodets [167]

Answer:

Step-by-step explanation:

For the zeros, c is shows the correct number of zeros -- 7.

But you should note that the answer ought to contain the correct number of sig digs. There are 3. 692 The 2 cannot be dropped. Still your answer is correct.

3 0
2 years ago
Which pair of numbers are not opposites?
Vinvika [58]
A
The absolute value of -27 is 27, so it is the same number
7 0
3 years ago
Read 2 more answers
A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 6%
Georgia [21]

Answer:

a

\% E =  0.9 \%

b

\%E_1 = 10.1 \%

Step-by-step explanation:

From the question we are told that

The probability that an employees suffered lost-time accidents last year is P(e) =  0.06

The probability that an employees suffered lost-time accident during the current year is

P(c) =  0.05

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

P(c | e) =  0.15

Generally the probability that an employee will experience lost time in both year is mathematically represented as

P(c \ n \ e) =  P(e) *  P(c \ |\ e)

=> P(c \ n \ e) =  0.06*   0.15

=> P(c \ n \ e) = 0.009

Generally the percentage of employees that will experience lost time in both year is mathematically represented as

\% E =  P(e \ n \ c ) * 100

=> \% E =  0.009 * 100

=> \% E =  0.9 \%

Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

P(e \ u \ c) =  P(e) + P(c) - P(e \ n \  c)

=> P(e \ u \ c) =  0.06 + 0.05 - 0.009

=> P(e \ u \ c) =  0.101

Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

\%E_1 = P(e \ u \ c) *  100

=> \%E_1 = 0.101*  100

=> \%E_1 = 10.1 \%

7 0
3 years ago
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