Answer:
the company must buy 22 gallons to paint this entire area
Step-by-step explanation:
The circumference of the tank is given and is C = 2(pi)r, where r is the area.
118 ft
Here the circumference is C = 2(pi)(r) = 118 ft, which leads to r = ------------ ≈
18.79 ft ≈ r 2(pi)
The area of the sides is A = (circumference)(height), or approximately
(118 ft)(50 ft) = 5900 ft², and the area of the top is A = πr², which here comes to (π)(18.79 ft)² ≈ 1109 ft². Combining these two sub-areas, we get:
A(total) = 1109 ft² + 5900 ft² ≈ 7009 ft²
To determine how many gallons of paint will be needed to paint only the top and sides, we divide 7009 ft² by the coverage rate, which is
320 ft²
-----------
1 gallon
which results in:
7009 ft²
---------------------- ≈ 21.9 gallons
320 ft² / gallon
Since the paint comes only in full gallon cans, the company must buy 22 gallons to paint this entire area.
Answer:
45
Step-by-step explanation:
This is a trick question. Since they only get three purchases in by 7 weeks, the answer will be 15 times 3 or 45.
(If I'm wrong and it's not a trick question, then it's 15 times 3.5 or 52.5)
Hope this helps!
The volume of a cylinder is given by the multiplication of the area of the base by the height of the cylinder. π×r²(area of the base) × h (height of the cylinder) ⇔
×
cm²×35cm=12127.5cm³
(r is half of the diameter. Because we are doing the square of r, the cm also are squared.)
Rounding to the nearest tenth is to round the result so that it maintains a number after the point - the result is 12127.5cm³
Yint is where the line crosses the y axis or where x=0
set x=0
3y+4x=15
x=0
3y+4(0)=15
3y+0=15
3y=15
divide by 3
y=5
yint is (0,5) or at y=5
