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3 years ago

10.76568623 to the nearest hundred place

Mathematics

2 answers:

garri49 [273]3 years ago

8 0

Answer:

10.77

Step-by-step explanation:

Find the number in the hundredth place 6 and look one place to the right for the rounding digit 5. Round up if this number is greater than or equal to 5 and round down if it is less than 5.

choli [55]3 years ago

3 0

Answer:

Step-by-step explanation:

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\left(x+3,\ y-6\right).

erastovalidia [21]

Say left is your mom and that would mean the answer would be 38922938829

3 0

2 years ago

What is the square root of 465

kaheart [24]

Answer:

The square root of 465 with one digit decimal accuracy is 21.5.

Step-by-step explanation:

√465 = 21.5

3 0

2 years ago

Read 2 more answers

Triangle ABC is shown below.<br> What is the length of line segment AC?

Rzqust [24]

Answer:

The length of the line segment AC is equal to 14

Step-by-step explanation:

The triangle above is an isosceles triangle, In an Isosceles triangle the two angles; B and C are the same, hence the two sides; AB and AC are also the same.

AB=2x and AC= 3x - 7

AB = AC

which implies;

2x = 3x - 7

subtract 3x from both-side of the equation

2x - 3x = 3x -3x -7

-x = -7

Multiply through by -1

x = 7

But we were ask to find the the length of the line segment AC

AC = 3x - 7

substituting x = 7 into the above equation will yield;

AC = 3(7) - 7 = 21 - 7 =14

Therefore the length of the line segment AC is equal to 14

3 0

3 years ago

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$