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bixtya [17]
3 years ago
7

Find the geometric mean of 11 and 23. Round your answer to the nearest tenth.

Mathematics
1 answer:
djyliett [7]3 years ago
4 0

Answer: 15

Step-by-step explanation:

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After a baby was born, he began to gain weight at a rate of 1.5 pounds per month. The
myrzilka [38]

Answer:

W(t) = 10 + 1.5*t

Step-by-step explanation:

Given:

The weight gain of the baby is 1.5 pounds per month.

After 4 months, baby's weight = 16 pounds

Let us the say the weight of the baby when it was born be x.

Then:

x + 1.5*(4) = 16

x = 10

Then weight of the baby as a function of number of months(t) will be=

initial weight + incremental weight per month*no of months(t).

W(t) = 10 + 1.5*t

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AssAssessment captures blank growth
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3 years ago
A computer programming team has 13 members. a. How many ways can a group of seven be chosen to work on a project? b. Suppose sev
Julli [10]

Answer:

1716 ;

700 ;

1715 ;

658 ;

1254 ;

792

Step-by-step explanation:

Given that :

Number of members (n) = 13

a. How many ways can a group of seven be chosen to work on a project?

13C7:

Recall :

nCr = n! ÷ (n-r)! r!

13C7 = 13! ÷ (13 - 7)!7!

= 13! ÷ 6! 7!

(13*12*11*10*9*8*7!) ÷ 7! (6*5*4*3*2*1)

1235520 / 720

= 1716

b. Suppose seven team members are women and six are men.

Men = 6 ; women = 7

(i) How many groups of seven can be chosen that contain four women and three men?

(7C4) * (6C3)

Using calculator :

7C4 = 35

6C3 = 20

(35 * 20) = 700

(ii) How many groups of seven can be chosen that contain at least one man?

13C7 - 7C7

7C7 = only women

13C7 = 1716

7C7 = 1

1716 - 1 = 1715

(iii) How many groups of seven can be chosen that contain at most three women?

(6C4 * 7C3) + (6C5 * 7C2) + (6C6 * 7C1)

Using calculator :

(15 * 35) + (6 * 21) + (1 * 7)

525 + 126 + 7

= 658

c. Suppose two team members refuse to work together on projects. How many groups of seven can be chosen to work on a project?

(First in second out) + (second in first out) + (both out)

13 - 2 = 11

11C6 + 11C6 + 11C7

Using calculator :

462 + 462 + 330

= 1254

d. Suppose two team members insist on either working together or not at all on projects. How many groups of seven can be chosen to work on a project?

Number of ways with both in the group = 11C5

Number of ways with both out of the group = 11C7

11C5 + 11C7

462 + 330

= 792

8 0
2 years ago
Help me please don’t need an explanation just a quick answer
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3 years ago
Margo won 24 out of her last 36 tennis matches.At this rate,predict how many matches she would win out of her next 27 matches ?
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27 out of 39 win i guess If u think this is right ok
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