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BabaBlast [244]
3 years ago
13

The The point (2,6) is on the line given by which equation below?

Mathematics
1 answer:
maria [59]3 years ago
3 0

Answer:

A  y = 3x

Step-by-step explanation:

We can check each line to see if the point is on it

A  y = 3x  6 = 2*3  6=6  this is true so the point is one the line

B  y = 4-x   6 = 2-4  6 = -2  false

C  y = -3x   6 = -3(2)  6=-6  false

D  y =-x+4   6 = -2+4   6 = 2  false

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Step-by-step explanation:

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6/-4   (right 6 points on x-axis & down 4 points on y- axis

Step-by-step explanation:

14- 8            6

---------- =    ------

5-9             - 4

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Which of the following equations are equivalent to -2m - 5m - 8 = 3 + (-7) + m?
aleksandrvk [35]
To solve this problem, we must simplify the the equation:
<span>Here is the base equation -2m - 5m - 8 = 3 + (-7) + m (Add all like terms):

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#2 -7m - 8 = -4 + m (Most Simplified Equation)

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3 0
3 years ago
Read 2 more answers
A communications channel transmits the digits 0 and 1. However, due to static, the digit transmitted is incorrectly received wit
m_a_m_a [10]

Answer:

The probability that the message will be wrong when decoded is 0.05792

Step-by-step explanation:

Consider the provided information.

To reduce the chance or error, we transmit 00000 instead of 0 and 11111 instead of 1.

We have 5 bits, message will be corrupt if at least 3 bits are incorrect for the same block.

The digit transmitted is incorrectly received with probability p = 0.2

The probability of receiving a digit correctly is q = 1 - 0.2 = 0.8

We want the probability that the message will be wrong when decoded.

This can be written as:

P(X\geq3) =P(X=3)+P(X=4)+P(X=5)\\P(X\geq3) =\frac{5!}{3!2!}(0.2)^3(0.8)^{2}+\frac{5!}{4!1!}(0.2)^4(0.8)^{1}+\frac{5!}{5!}(0.2)^5(0.8)^0\\P(X\geq3) =0.05792

Hence, the probability that the message will be wrong when decoded is 0.05792

4 0
3 years ago
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lukranit [14]
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- x^4             - x²
------------------------
          - 4 x³ + x² - 4 x
            4 x³        + 4 x
         -----------------------
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                   - x²   - 1
                ----------------
                   R ( x ) = 0
( x^4 - 4 x³ + 2 x² - 4 x + 1) =  ( x² + 1 ) ( x² - 4 x + 1 )
3 0
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