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Mrrafil [7]
3 years ago
8

9,2 and 4,9 simplify answer

Mathematics
1 answer:
EleoNora [17]3 years ago
7 0
If your talking about fraction just find a common number the tow fractions have and divide
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Solve this rational equation ​
tino4ka555 [31]

Answer:

<h2>x = -1</h2>

Step-by-step explanation:

\text{Domain:}\\\\x-4\neq0\ \wedge\ x-2\neq0\ \wedge\ x^2-6x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x^2-4x-2x+8\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x(x-4)-2(x-4)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ (x-4)(x-2)\neq0\\\\x\neq4\ \wedge\ x\neq2\ \wedge\ x-4\neq0\ \wedge\ x-2\neq0\\\\\boxed{D:x\neq4\ \wedge\ x\neq2}

\dfrac{1}{x-4}+\dfrac{x}{x-2}=\dfrac{2}{x^2-6x+8}\\\\\dfrac{1(x-2)}{(x-4)(x-2)}+\dfrac{x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\\\\\dfrac{x-2+x(x-4)}{(x-4)(x-2)}=\dfrac{2}{(x-4)(x-2)}\iff x-2+x(x-4)=2\\\\x-2+(x)(x)+(x)(-4)=2\\\\x-2+x^2-4x=2\qquad\text{subtract 2 from both sides}\\\\x^2-3x-4=0\\\\x^2-4x+x-4=0\\\\x(x-4)+1(x-4)=0\\\\(x-4)(x+1)=0\iff x-4=0\ \wedge\ x+1=0\\\\x-4=0\qquad\text{add 4 to both sides}\\x=4\notin D\\\\x+1=0\qquad\text{subtract 1 from both sides}\\x=-1\in D

8 0
3 years ago
Find the common difference in the arithmetic sequence where p35 =-9p + 4 and p28 = 5p - 17?
Sphinxa [80]
P(35) = -9p + 4 = -9(35) + 4 = -315 + 4 = -311
p(28) = 5p - 17 = 5(28) - 17 = 140 - 17 = 123

a + 34d = -311
a + 27d = 123

7d = -434
d = -62

Therefore, the commpm difference is -62.
6 0
3 years ago
3 square root of negative 125
Leni [432]
The answer is 33.5410197i
6 0
3 years ago
What is the value of p?<br> (Geometry Question)
Keith_Richards [23]

Answer:

p = 92

Step-by-step explanation:

The exterior angle of a triangle is equal to the sum of the opposite interior angle

p+45 = (p-47)+p

Combine like terms

p+45 = 2p-47

Subtract p from each side

p-p+45 = 2p-p-47

45 = p-47

Add 47 to each side

45+47 = p-47+47

92 = p

6 0
4 years ago
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre
luda_lava [24]

Answer:

Match the number of statement with the same number of reasons.

Step-by-step explanation:

Here are the statements

1.

Points R, S, T, Q on circle O

2.

measure of RS+ST=RT

measure of RT+TQ=RQ

3.RS+ST+TQ=RQ

Here are the reasons

1.Given

2. Arc Addition

3. Subsitution

6 0
3 years ago
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