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NISA [10]
3 years ago
13

What is the correct order of operations for simplifying the expression (x+3)^2-(x^2+9)/2x^2?

Mathematics
1 answer:
Contact [7]3 years ago
3 0

The expression simplified is \frac{3}{x}

Step-by-step explanation:

The expression given in this problem is

\frac{(x+3)^2-(x^2+9)}{2x^2}

We proceed in the following way:

- First, we solve the square of the brackets:

\frac{x^2+6x+9-x^2-9}{2x^2}

- Now we add/subtract the similar terms:

\frac{(x^2-x^2)+6x+(9-9)}{2x^2}=\frac{6x}{2x^2}

- And now we simplify by 2x, and we get:

\frac{6x}{2x^2}=\frac{3}{x}

Learn more about simplification:

brainly.com/question/7014769

brainly.com/question/1430645

#LearnwithBrainly

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3 years ago
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Vesnalui [34]

Answer:

8/4

Step-by-step explanation:

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hope this helps!

5 0
3 years ago
Read 2 more answers
Consider the following functions.G(x) = 4x2; f(x) = 8x(a)
noname [10]

Answer:

(a) B. G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

(b) Every function of the form 4x^2+C is an antiderivative of 8x

Step-by-step explanation:

A function <em>F </em>is an antiderivative of the function <em>f</em> if

F'(x)=f(x)

for all x in the domain of <em>f.</em>

(a) If f(x) = 8x, then G(x)=4x^2 is an antiderivative of <em>f </em>because

G'(x)=8x=f(x)

Therefore, G(x) is an antiderivative of f(x) because G'(x) = f(x) for all x.

Let F be an antiderivative of f. Then, for each constant C, the function F(x) + C is also an antiderivative of <em>f</em>.

(b) Because

\frac{d}{dx}(4x^2)=8x

then G(x)=4x^2 is an antiderivative of f(x) = 8x. Therefore, every antiderivative of 8x is of the form 4x^2+C for some constant C, and every function of the form 4x^2+C is an antiderivative of 8x.

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4 years ago
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