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aalyn [17]
3 years ago
10

In the standard (x,y) coordinate plane, what is the area of the circle x^2 + y^2 =169?

Mathematics
1 answer:
schepotkina [342]3 years ago
6 0

Answer:

169π

Step-by-step explanation:

circle eq: (x-a)²+(y-b)²=r², where (a,b) is center and r is radius

r²=169

r = ±13

since a radius length must be positive, r = +13, not -13

A of circle: πr²

r = 13

169π

given that the circle eq has r², you could've noticed that you can take the constant in the circle eq and multiply that by π to get the same answer

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anzhelika [568]

Answer:

<h2><u>b = 2 or b = -2</u></h2>

Explanation:

|4b + 4| = |2b + 8|

<em>Solve absolute value</em>

|4b + 4| = |2b + 8|

Either 4b + 4 = 2b + 8 or 4b + 4 = −(2b + 8)

4b + 4 = 2b + 8 <em>(Possibility 1)</em>

4b + 4 − 2b = 2b + 8 − 2b <em>(Subtract 2b from both sides)</em>

2b + 4 = 8

2b + 4 − 4 = 8 − 4 <em>(Subtract 4 from both sides)</em>

2b = 4

2b / 2 = 4 / 2 <em>(Divide both sides by 2)</em>

b = 2

4b + 4 = −(2b + 8) <em>(Possibility 2)</em>

4b + 4 = −2b − 8 <em>(Simplify both sides of the equation)</em>

4b + 4 + 2b = −2b − 8 + 2b <em>(Add 2b to both sides)</em>

6b + 4 = −8

6b + 4 − 4 = −8 − 4 <em>(Subtract 4 from both sides)</em>

6b = −12

6b / 6 = -12 / 6 <em>(Divide both sides by 6)</em>

b = -2

<h2><u>b = 2 or b = -2</u></h2>
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3 years ago
Suppose you are going to graph the data in the table below. What data should be represented on each axis, and what should the in
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The measure of an angle is 133°. What is the measure of its supplementary angle?
Pachacha [2.7K]

Answer:

47

Step-by-step explanation:

180 - 133 = 47

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Step-by-step explanation:

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The bases of a trapezoid lie on the lines y=2X +7 and y= 2X -5. Write the equation that contains the midsegment of the trapezoid
ryzh [129]

Given:

The bases of a trapezoid lie on the lines

y=2x+7

y=2x-5

To find:

The equation that contains the midsegment of the trapezoid.

Solution:

The slope intercept form of a line is

y=mx+b

Where, m is slope and b is y-intercept.

On comparing y=2x+7 with slope intercept form, we get

m_1=2,b_1=7

On comparing y=2x-5 with slope intercept form, we get

m_2=2,b_2=-5

The slope of parallel lines are equal and midsegment of a trapezoid is parallel to the bases. So, the slope of the bases line and the midsegment line are equal.

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The y-intercept of one base is 7 and y-intercept of second base is -5. The y-intercept of the midsegment is equal to the average of y-intersects of the bases.

b=\dfrac{b_1+b_2}{2}

b=\dfrac{7-5}{2}

b=\dfrac{2}{2}

b=1

So, the y-intercept of the required line is 1.

Putting m=2 and b=1 in slope intercept form, we get

y=2x+1

Therefore, the equation of line that contains the midsegment of the trapezoid is y=2x+1.

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