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3 years ago

In the standard (x,y) coordinate plane, what is the area of the circle x^2 + y^2 =169?

Mathematics

1 answer:

schepotkina [342]3 years ago

6 0

Answer:

169π

Step-by-step explanation:

circle eq: (x-a)²+(y-b)²=r², where (a,b) is center and r is radius

r²=169

r = ±13

since a radius length must be positive, r = +13, not -13

A of circle: πr²

r = 13

169π

given that the circle eq has r², you could've noticed that you can take the constant in the circle eq and multiply that by π to get the same answer

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Consider the following polynomial functions.<br> f(a) = (2a - 7 + a?) and g(a) = (5 – a).

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Answer:

1 false

2 true

3 true

4 false

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Step-by-step explanation:

f(a) = (2a - 7 + a^2) and g(a) = (5 – a).

1 false f(a) is a second degree polynomial and g(a) is a first degree polynomial

When added together, they will be a second degree polynomial

2. true When we add and subtract polynomials, we still get a polynomial, so it is closed under addition and subtraction

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Combining like terms = a^2 +a -2

4. false f(a) - g(a) = (2a - 7 + a^2) - (5 – a)

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nexus9112 [7]

Answer:

x= -6

Step-by-step explanation:

-2x-14=-2

We move all terms to the left:

-2x-14-(-2)=0

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We move all terms containing x to the left, all other terms to the right

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lesya [120]

Answer:

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B={(2,2),(4,2),(6,2),(2,4),(2,6),(1,3),(1,5),(1,1),(3,1),(3,3),(3,5),(4,4),(4,6),(5,1),(5,3),(5,5),(6,4),(6,6)}

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Step-by-step explanation:

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