Answer with Step-by-step explanation:
We are given that if sum of several numbers is odd
We have to prove that at least one of the number is itself odd.
Suppose, we have three numbers
a=6 , b=7,d=8
Sum of numbers=6+7+8=21=Odd number
We know that sum of two odd numbers is always an even number.
Sum of an odd number and an even number is always an odd number.
If we take even odd numbers then sum is always an even number and sum of odd odd numbers then the sum is always an odd number.


Sum of even numbers is always an even number.
Hence, there are atleast one numebr is odd then the sum of several number is odd.
Answer:
or 
Step-by-step explanation:
We need to divide 300 by 20.
We get
or
.
Answer:
48f^2-110f+63
Step-by-step explanation:
We multiple every part of first sum with every prt of the 2nd sum:
(6f-7)(8f-9)=48f^2-54f-56f+63=
48f^2-110f+63
Answer:
336
Step-by-step explanation:
The graph will be discrete because there is no such thing as a partial person to sign up and the booth is set up once each day for sign ups. So the last answer choice is the right one