A theme is

Mathematics

2 answers:

mezya [45]2 years ago

5 0

Answer is b hope it helps

Vilka [71]2 years ago

4 0

B one message convey throught the text

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The wettest April for Albuquerque, NM, was recorded in 1905. The amount was 1.2in more than the amount recorded for the second w

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The 1905 was 3.0 inches while 2004 was 4.2 inches since they are 1.2 apart and they add up to 7.2

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A table showing Number, Value, and Total Value. The first row shows Pennies, with the entries, p, 0.01, and 0.01 p. The second r

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Answer:

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Step-by-step explanation:

B on edge

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3 years ago

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A marketing researcher wants to find a 96% confidence interval for the mean amount those visitors spend per person per day while

ki77a [65]

Answer:

$n=(\frac{2.054(12)}{4})^2 =37.97 \approx 38$

So then the minimum sample to ensure the condition given is n= 38

Step-by-step explanation:

Notation

$\bar X$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=12$ represent the population standard deviation

n represent the sample size

ME = 4 the margin of error desired

Solution to the problem

When we create a confidence interval for the mean the margin of error is given by this formula:

$ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (a)

And on this case we have that ME =4 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

$n=(\frac{z_{\alpha/2} \sigma}{ME})^2$ (b)

The critical value for 96% of confidence interval now can be founded using the normal distribution. The significance is $\alpha=1-0.96 =0.04$ . And in excel we can use this formula to find it:"=-NORM.INV(0.02;0;1)", and we got $z_{\alpha/2}=2.054$ , replacing into formula (b) we got: