What is f(x)=3x^2-18x+23 into vertex form

1 answer:

5 0

$3x^2-18x+23=3(x^2-6x)+23=3(x^2-6x+9-9)+23$
$\quad=3((x-3)^2-9)+23=3(x-3)^2-27+23=3(x-3)^2-4$

The vertex is then $(3,-4)$ .

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