Question

¿Cuántos gramos de H2O habrá en 3,0115x1023 moléculas de agua?

Answer 1

Answer : The weight of water is 9 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given molecules}}{\text{avogadro's number}}=\frac{3.0115\times 10^{23}}{6.023\times 10^{23}}=0.5moles$

1 mole of water $(H_2O)$ weighs = 18 g

0.5 moles of water$(H_2O)$ weighs = $\frac{18}{1}\times 0.5=9g$

Thus the weight of water is 9 g