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3 years ago

If a=-2 and b=1, then 3a-2b=

Mathematics

2 answers:

Akimi4 [234]3 years ago

6 0

If a=-2 and b=1, then
3a-2b
= 3(-2) -2(1)
= -6 -2
= -8

Thepotemich [5.8K]3 years ago

6 0

The answer would come down to be 3(-2)-2(1), simplifying to -8

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Given that the functions $f(x)=x+4$ and $g(x)=x^{3}$

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First, we shall determine the composition of the function $(g \circ f)(x)$

Function $(g \circ f)(x)$ :

Let us determine the function $(g \circ f)(x)$

Thus, we have;

$(g \circ f)(x)=g[f(x)]$

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Thus, the function is $(g \circ f)(x)=x^3+12x^2+48x+64$

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The value of the function can be determined by substituting x = -3 in the function $(g \circ f)(x)=x^3+12x^2+48x+64$

Thus, we have;

$(g \circ f)(-3)=(-3)^3+12(-3)^2+48(-3)+64$

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