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anyanavicka [17]
3 years ago
12

Cos^6A+sin^6A=1/4 (1+3cos^2 2A)=1/8 (5+3cos4A​)

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
8 0

Answer:

cos^6A+sin^6A=1/4 (1+3cos^2 2A)=1/8 (5+3cos4A​) = True

Step-by-step explanation:

Solve for A:

cos^6(A) + sin^6(A) = 1/4 (3 cos^2(2 A) + 1)

Hint: | Expand out terms of the right hand side.

1/4 (3 cos^2(2 A) + 1) = 3/4 cos^2(2 A) + 1/4:

cos^6(A) + sin^6(A) = 3/4 cos^2(2 A) + 1/4

Hint: | Move everything to the left hand side.

Subtract 3/4 cos^2(2 A) + 1/4 from both sides:

-1/4 + cos^6(A) - 3/4 cos^2(2 A) + sin^6(A) = 0

Hint: | Write the left hand side as a single fraction.

Bring -1/4 + cos^6(A) - 3/4 cos^2(2 A) + sin^6(A) together using the common denominator 4:

1/4 (-1 + 4 cos^6(A) - 3 cos^2(2 A) + 4 sin^6(A)) = 0

Hint: | Multiply both sides by a constant to simplify the equation.

Multiply both sides by 4:

-1 + 4 cos^6(A) - 3 cos^2(2 A) + 4 sin^6(A) = 0

Hint: | Rewrite the left hand side.

Expand trigonometric functions:

0 = 0

Hint: | Look for a true statement.

0 = 0 is trivially true:

Answer: True

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HI PLEASE HELP ME WITH MY CALCULUS 1 HW? I AM REALLY STUCK. I need help with parts d,e,g.
asambeis [7]

(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

(e) The total distance traveled is obtained by integrating the absolute value of the velocity function over the given interval:

\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

which follows from the definition of absolute value. In particular, if x is negative, then |x|=-x.

The total distance traveled is then 4 ft.

(g) Acceleration is the rate of change of velocity, so a(t) is the derivative of v(t):

a(t)=v'(t)=-\dfrac{\pi^2}9\cos\left(\dfrac{\pi t}3\right)

Compute the acceleration at t=4 seconds:

a(t)=\dfrac{\pi^2}{18}\dfrac{\rm ft}{\mathrm s^2}

(In case you need to know, for part (i), the particle is speeding up when the acceleration is positive. So this is done the same way as part (d).)

6 0
3 years ago
Complete the equation of the line through (-8-2) and (-4-6)
Kisachek [45]

Answer:

Step-by-step explanation:

since you are given two points use the point- slope formula and the slope formula

y-y1 = m( x -x1)   and  m = y2 -y1 / x2 - x1        

find the slope m, 1st

p1 = (x1,y1)  given (-8,-2)

p2 = (x2,y2) given (-4,-6)

m = -6-(-2) / -4-(-8)

m = -6+2 / -4+8

m = -4 / 4

m = -1  :)

now use the slope you just found and the point-slope with either given point.. pick one.. which ever seems easier... they seem about the same to me

y - (-8) = -1(x-(-2))

y+8 = -1(x+2)

y+8 = -x-2

y = -x-2-8

y= -x-10

and your done :)

4 0
3 years ago
Pls help answer....
emmainna [20.7K]

Answer: 18

Step-by-step explanation: 4/3 times 6/5

Is 8/3, flip to 3/8. Use galgo technique: 18

5 0
3 years ago
What is 8.517 in expanded form
Maru [420]
Eight and five hundred seventeen thousandths.
5 0
3 years ago
79.99 - 12% + 8%<br> please dhow your work<br> thank you<br> And be safe
Sergeu [11.5K]

Answer:

79.95

Step-by-step explanation:

The first step is to rewrite the percentages into decimals so they can be added or subtracted easier. To turn a percentage into a decimal, remove the percent sign and move the decimal two spaces to the left (in other words, divide the number by 100).

12% becomes -0.12

8% becomes 0.08

Now, let's solve.

79.99 - 0.12 + 0.08

Evaluating 79.99 - 0.12, the equation becomes 79.87 + 0.08.

Evaluating 79.87 + 0.08, we get the final answer, 79.95.

8 0
3 years ago
Read 2 more answers
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