For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
Simple, first find a common denominator, 24.
So,
7/4*6= 42/24
and
5/6*6=30/24
Then just add,
42/24
+
30/24
Making it 72/24.
72/24=3
Thus, your answer is, 3.
Answer:
5-2√10
Step-by-step explanation:
5-2√10
break them down
√25=5
so 5-√40
then simplify
5-2√10
Answer:
3:6
Step-by-step explanation:
8:24 and 24:72 reduce down to 1:3. 3:6 is 1:2.
Answer:
The original number is 5.
Step-by-step explanation:
When you double 5, you get 10. And 10 is 5 more than 5.