Which is greater 2/3 or 3/4

In a Match 6 Lotto, winning the jackpot requires that you select six different numbers from 1 to 49, and that the same six numbe

zimovet [89]

Answer:

$P=\frac{1}{13,983,816}=7.2\ x\ 10^{-8}$

Step-by-step explanation:

Consider the following characteristics of the problem:

The numbers that are selected are different between 1 and 49. This means that the same number is not repeated twice.

The order in which the selected numbers appear does not matter:

This means that (123) = (312)

With this in mind, we know that it is a problem of combinations without repetition. It is not calculated using permutations because in the permutations the order of selection is important, for example: (123) is not equal to (312)

The formula for calculating combinations without repetition is:

$nCr=\frac{n!}{r!(n-r)!}$

Where n is the number of "elements" you can choose and choose r from them

In this case:

n=49

r=6

So:

$49C6=\frac{49!}{6!(49-6)!}$

$49C6=13,983,816\ outcomes$

There are 13,983,816 possible results

This is the best method to calculate the number of possible outcomes.

<em><u>"Besides your method, is there another method to determine the number of outcomes?"</u></em>

Sure, make a list of the 13,983,816 different sets of 6 numbers.

To win it is necessary to obtain the 6 winning numbers in any order. The number of ways this can occur is calculated by combining 6 in 6

$6C6=\frac{6!}{6!(6-6)!}=1$

Finally the probability of winning is:

$P=\frac{1}{13,983,816}=7.2\ x\ 10^{-8}$

Note that the probability of winning is very close to 0. It is practically impossible to win the lottery, you will probably never win anything. Therefore it is better not to invest money in this

6 0

3 years ago

if a, b, and c are prime numbers, do (a b) and c have a common factor that is greater than 1? (1) a, b, and c are all different

klio [65]

If a,b, and c are prime numbers, do (a*b) and c have a common factor that is greater than 1

(1) a,b, and c are all different prime numbers

(2) c≠2

1. Let's assume values of 1,3 and 5 to a, b, and c respectively

a b = 1*3 = 3

3 and 5 do not have any common factor aside 1

Let's assume values of 1,3 and 2 to a,b and c respectively

a *b = 1*3 = 3

3 and 2 does not have a common factor aside 1

2. c $\neq$ 2

Let's assume values of 2,7 and 3 to a b and c response

a * b = 2 *7 = 14

14 and 3 does not have a common factor aside 1

learn more about of prime number here

brainly.com/question/14410795

#SPJ4

8 0

1 year ago

Probability. A professor rides his bike to work some days and drives his car on the other days. On any day there is an 80% chanc

Artyom0805 [142]

Answer:

0.09

Step-by-step explanation:

Given :

P(bike) = 0.8

P(car) = 0.2

P(Late given car) = P(Late | car) = 0.05

P(Late given bike) = p(Late | bike) = 0.1

Probability that professor is late :

P(late) = [P(Late | car) * p(car)] + [p(Late | bike) * p(bike)]

P(late) = [0.05 * 0.2] + [0.1 * 0.8]

P(late) = 0.01 + 0.08

P(late) = 0.09

3 0

3 years ago

PLEASE HELP I DON'T UNDERSTAND! A florist is making regular bouquets and mini bouquets. The florist has 118 roses and 226 peonie

Anna [14]

Answer:

The florist can make 11 regular bouquets and 21 mini bouquets

Step-by-step explanation:

The number of roses the florist has = 118 roses

The number of peonies the florist has = 226 peonies

The number of roses in each regular bouquet = 5 roses

The number of peonies in each regular bouquet = 11 peonies

The number of roses in each mini bouquet = 3 roses

The number of peonies in each mini bouquet = 5 peonies

1. The equation that gives the total number of roses to be used in both kinds of bouquet is given as follows;

Let r represent the number of regular bouquet the florist can make and let m represent the number of mini bouquet the florist can make, we have;

5·r + 3·m = 118...(1)

2. Similarly, we have;

11·r + 5·m = 226...(2)

Making m the subject of the formula of both equations, and equating both values of m to find a common solution, we have;

m = (118 - 5·r)/3

m = (226 - 11·r)/5

(118 - 5·r)/3 = (226 - 11·r)/5

5 × (118 - 5·r) = 3 × (226 - 11·r)

590 - 25·r = 678 - 33·r

33·r - 25·r = 678 - 590 = 88

8·r = 88

r = 88/8 = 11

r = 11

The number of regular bouquet the florist can make = r = 11

m = (118 - 5·r)/3 = (118 - 5×11)/3 = 21

m = 21

The number of mini bouquet the florist can make = m = 21

The number of regular bouquet the florist can make = 11 bouquets

The number of mini bouquet the florist can make = 21 bouquets.

3 0

2 years ago

PLEASE HELP, BEEN STUCK FOR AN HOUR

djverab [1.8K]

Answer:

Step-by-step explanation:

To sketch a quadratic function we need two things:

1) Nature of the curve

2) Vertex

3) y-intercept

The completing square form of the quadratic equation is:

$y=a(x-h)^2+k$

where,

a represents the nature of the graph it can be maximum or minimum , meaning, if a > 0 then minimum(u shaped curve/happy face) and if a < 0 then maximum(n shaped curve/sad face).

h represents the x-coordinate of the vertex.

k represents the y-coordinate of the vertex.

Now if we compare g(x) with our completing square form we get the following:

$g(x)=(x-4)^2+12\\y=a(x-h)^2+k\\$

When we simply compare the following we get ,

a = 1 , which means a > 0 since 1 is greater than 0 the nature of the curve will be minimum(happy face/u shaped)

h = 4, which means the x-coordinate of the vertex is 4

k = 12, which means the y-coordinate of the vertex is 12

Now we have the nature of the curve, we have the vertex now all we need is the y-intercept.

For y-intercept:

For y-intercept meaning at which point will the graph cross the y-axis(0 , y)

For that we expand the formula and turn it into the standard quadratic equation form by using the formula (a - b)^2

$y=(x-4)^2+12\\y=((x)^2-2(x)(4)+(4)^2)+12\\y=x^2-8x+16+12\\y=x^2-8x+28\\$

now we compare with the standard quadratic form:

$y=ax^2+bx+c$

here c is the y-intercept and while comparing we can see that c = 28 ,

so the curve cuts the y-axis at (0 , 28)

So we have all the three things that we need to graph our function.

So we just plot the y-intercept , the vertex , and join the dots. Just a tip draw a dotted line on the x-coordinate of the vertex because the vertex point is also called as a turning point where the graph goes in the opposite direction just like a mirror reflection. I attached 2 images you can check them out. One is handmade(i know i suck at drawing but still xD) , one is sketched by online graphing calculator.

5 0

3 years ago