Given :
C, D, and E are col-linear, CE = 15.8 centimetres, and DE= 3.5 centimetres.
To Find :
Two possible lengths for CD.
Solution :
Their are two cases :
1)
When D is in between C and E .
. . .
C D E
Here, CD = CE - DE
CD = 15.8 - 3.5 cm
CD = 12.3 cm
2)
When E is in between D and C.
. . .
D E C
Here, CD = CE + DE
CD = 15.8 + 3.5 cm
CD = 19.3 cm
Hence, this is the required solution.
Only 1 and 51 are factors of 51.
Answer:
refer to explanation
Step-by-step explanation:
the lengths of the base and height are the factors of 20
so they can be 5×4, 10×2, 1×20
Volume of the shape
= 4ft * 4ft * 15ft
= 240ft³
