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katen-ka-za [31]
3 years ago
6

What's the area of this? PLS HELP

Mathematics
2 answers:
Ilya [14]3 years ago
4 0

Answer:

area: 446mm

Step-by-step explanation:

split up the shape into squares, find the area of those, add it all together to get the total area

balandron [24]3 years ago
3 0

Answer:

446mm

Step-by-step explanation:

If we box off parts of the area, it makes it easier to solve. I personally broke it into tiny bits:

Upper left box: 16mm

Bigger box (excluding little box): 90mm

Big rectangle: 340mm

Now, add them all together.

Equals 446mm

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HELP PLEASE!! which of the following represents a function?
PolarNik [594]
The answer would be A because each x only has one y. Hope that makes sense!
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Hi can anyone pls help me in dis math problem I WILL MARK U AS BRAINLEIST!!!
ivanzaharov [21]

Answer:

Triangles A & C are right triangles.

Step-by-step explanation:

Triangles A & C are right triangles because they make a 90 degree angle were a pair of legs intersect. That box in the corner of each triangle indicates that the triangle is 90 degrees, therefore a right triangle.  

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How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

3 0
3 years ago
How many solutions are there to the equation below?<br> 8x + 47 = 8(x + 5)
qaws [65]

Answer:

there are 0 solutions to the equation

Step-by-step explanation:

To know how many solutions are in the problem, we have to solve for x and see what result we have left. According to the result, we will know how many solutions there are

8x + 47 = 8(x + 5)

8x + 47 = 8*x + 8*5

8x + 47 = 8x + 40

8x - 8x = 40 - 47

0 = -7

As we can see we are left with an equality that is not fulfilled, this means that there is no solution to the problem, at least in the field of real numbers

4 0
3 years ago
NEEDED ASAP PLEASE HELP!
Ber [7]

Answer:

3rd choice

Step-by-step explanation:

x = 300 sales

1.3(300) = 301.30

20,000 + 301.30 = $20,301.30

7 0
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