Answer:
m∠P = 82°
m∠Q = 49°
m∠R = 49°
Step-by-step explanation:
<em>In the isosceles triangle, the base angles are equal in measures</em>
In Δ PQR
∵ PQ = PR
∴ Δ PQR is an isosceles triangle
∵ ∠Q and ∠R are the base angles
→ By using the fact above
∴ m∠Q = m∠R
∵ m∠Q = (3x + 25)°
∵ m∠R = (2x + 33)°
→ Equate them
∴ 3x + 25 = 2x + 33
→ Subtract 2x from both sides
∵ 3x - 2x + 25 = 2x - 2x + 33
∴ x + 25 = 33
→ Subtract 25 from both sides
∵ x + 25 - 25 = 33 - 25
∴ x = 8
→ Substitute the value of x in the measures of angles Q and R
∵ m∠Q = 3(8) + 25 = 24 + 25
∴ m∠Q = 49°
∵ m∠R = 2(8) + 33 = 16 + 33
∴ m∠R = 49°
∵ The sum of the measures of the interior angles of a Δ is 180°
∴ m∠P + m∠Q + m∠R = 180°
→ Substitute the measures of angles Q and R
∵ m∠P + 49 + 49 = 180
∴ m∠P + 98 = 180
→ Subtract 98 from both sides
∵ m∠P + 98 - 98 = 180 - 98
∴ m∠P = 82°
Answer:
option A)
(40, 96)
Step-by-step explanation:
Given that,
The coordinates of point K and J are
K(160,120)
J(-40,80)
x1 = 160
x2 = -40
y1 = 120
y2 = 80
P is (3/5) the line of the line segment from K to J
So, KP = (3/5) KJ and JP = (2/5) KJ
OR we will divide the length of KJ with the ratio 3 : 2 from K
m : n
3 : 2
m = 3
n = 2
by using this formula and putting values in it
xp = (m/m+n)(x2-x1) + x1
yp = (m/m+n)(y2-y1) + y1
xp = (3/3+2) (-40-160) + 160
yp = (3/3+2) (80-120) + 120
xp = 40
yp = 96
Answer:
Let x and y denotes the number of cabinet of the type X and Y. Then given problem can be formulated as, ☝
That is, the second pic
Sketch the region as 3 pic
Step-by-step explanation:
oh the same question was there by xxlunaxx4
You move the decimal over twice to get 63% and then put it over 100, 63/100 to get a fraction
