Considering the number of legs of each animal, it is found that there are 56 legs on the ground.
<h3>How many legs does each animal have?</h3>
Hence the number of legs on the ground is given by:
N = 2 x 4 + 4 x 9 + 1 x 4 + 1 x 2 + 3 x 2 = 56.
A similar problem, also involving the number of legs of each animal, is given at brainly.com/question/14010151
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SA = 2bA (base area) + LA (lateral area)
bA = r^2*pi = 13^2pi = 169pi cm^2
LA = 2r*pi*h = 2*13*pi*88,4 = 2298,4pi cm^2
SA = (2*169pi)+2298,4 pi = 338pi+2298,4pi = 2636,4pi
If you know that -2 is a zero of f(x) = x^3 + 7x^2 + 4x - 12, explain how to solve the equation.
First you have to figure out what could make f(x) = 0 to get rid of the cube. I'm going to test the array of data, x = -2, x = -3, and x = -4 because this type of equation probably has more negative values given that if you plug in some values the cubed-values and squared-values will surpass the "-12". Plug this into a calculator.
x^3 + 7x^2 + 4x - 12
f(-2) = -8 + 28 - 8 - 12 = 0
So you know that when x = -2, f(x) = 0. Divide "(x + 2)" from the equation and you will get... x^2 + 5x - 6. Now this is a simple polynomial one that you can figure to be (x + 6) (x - 1) just by looking at it because -6 multiplied by 1 is negative 6 and you see 5 and know that 6 - 1 = 5.
The solution is (x + 6) (x - 1) (x + 2) meaning that when x = -6, 1, or -2, f(x) is 0.
V=pie r square h/3
Hope you get the picture!
Step-by-step explanation:
∑k=150(3k+2)
First find a1 and a50 :
a1=3(1)+2=5a20=3(50)+2=152
Then find the sum:
Sk=k(a1 + ak)2S50=50(5 + 152)2=3925
