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ASHA 777 [7]
3 years ago
5

The focus of a parabola is (0, -3) and the directrix is y = 3. What is the equation of the parabola?

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0

Answer:

Step-by-step explanation:

the answer is D, just answered it and I got it right.

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When the temperature stays the same, the volume of a gas is inversely proportional to the pressure
pickupchik [31]
The answer is 14 pounds per square inch.
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3 years ago
Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar. The simplest form o
sleet_krkn [62]

Answer:

x

Step-by-step explanation:

-2x²(x – 5) + x(2x² – 10x) + x

The simplest for of the above equation can be obtained as follow:

-2x²(x – 5) + x(2x² – 10x) + x

Rearrange

x(2x² – 10x) – 2x²(x – 5) + x

Factorise

x.2x(x – 5) – 2x²(x – 5) + x

2x²(x – 5) – 2x²(x – 5) + x

Carry out the minus (–) operation

=> x

Therefore, the simplest form of expressing -2x2(x – 5) + x(2x2 – 10x) + x is x.

6 0
4 years ago
A ball dropped from the top of a building can be modeled by the function f(t)=-16^2+36, where t represents time in seconds
Viefleur [7K]

Answer:

The ball is dropped from a height of 36 feet

The bee and the ball will collide after approximately 1.3 seconds

The bee and the ball will collide at approximately 8 feet above the ground

The ball hits the ground after 1.5 seconds

Step-by-step explanation:

<u><em>The complete question is</em></u>

A ball dropped from the top of the building can be modeled by the function f(t)=-16t^2 + 36 , where t represents time in seconds after the ball was dropped. A bee's flight can be modeled by the function, g(t)=3t+4, where t represents time in seconds after the bee starts the flight.

The graph represents the situation.

select all that apply

1) The bee launches into flight from the ground.

2) The ball is dropped from a height of 36 feet.

3) The bee and the ball will collide after approximately 1.3 seconds.

4) The bee and the ball will collide after approximately 8 seconds.

5) The bee and the ball will collide at approximately 8 feet above the ground.

6) The bee and the ball will not collide.

7) The ball hits the ground after 1.5 seconds

see the attached figure to better understand the problem

<u><em>Verify all the options</em></u>

case 1) The bee launches into flight from the ground.

The statement is false

Because

we have

g(t)=3t+4

For t=0

g(t)=3(0)+4=4\ ft

That means ----> The bee launches into flight from a height 4 feet above the ground

case 2) The ball is dropped from a height of 36 feet

The statement is true

Because

For t=0

f(t)=-16(0)^2+36=36\ ft

case 3) The bee and the ball will collide after approximately 1.3 seconds

The statement is true

Because

Equate f(t) and g(t)

-16t^2+36=3t+4

-16t^2-3t+32=0

solve the quadratic equation by graphing

The solution is t=1.324 sec

see the attached figure N 2

case 4) The bee and the ball will collide after approximately 8 seconds

The statement is false

Because, the bee and the ball will collide after approximately 1.3 seconds (see case 3)

case 5) The bee and the ball will collide at approximately 8 feet above the ground

The statement is true

Because

For t=1.324 sec

substitute the value of t in f(t) or g(t)

g(t)=3(1.324)+4=7.97\ ft

case 6) The bee and the ball will not collide

The statement is false

see case 3) and case 5)

case 7) The ball hits the ground after 1.5 seconds

The statement is true

Because

we know that

The ball hit the ground when the value of f(t) is equal to zero

so

For f(t)=0

-16t^2+36=0

t^2=\frac{36}{16}

t=\frac{6}{4}=1.5\ sec

4 0
3 years ago
Read 2 more answers
Please help homework due
jolli1 [7]

Answer:

X≤3

Step-by-step explanation:

This is because the arrow is moving down the number line

3 0
2 years ago
Please help!!! Find the equation for all 4!!! It needs to be <br> Y=mx +b
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1) y= 2/5x -3
2) y= 2/3x + 1
3) y= 2x -1
4) y= 5/4x + 3
I think
7 0
3 years ago
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