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3 years ago

If x is a number which expression represents the statement 4 less than the product of 2 and a number

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

3 0

I think the expression that you need is, 4-(2x). Hope it helps!

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Which expressions represent Ernie's problem? Select each correct answer. 1500525 5251500 1500 ÷ 525 525 ÷ 1500 5251500 1500525

Kay [80]

Answer:

525 ÷ 1500 5251500

Step-by-step explanation:

3 0

3 years ago

Help finals study guide please I want to just go on break

timofeeve [1]

Step-by-step explanation:

(note: I'm only answering the ones I know vs giving you wrong answers for the others!)

1. ROS=Obtuse (larger then ninty degrees)

2. octagon has 8 angles (octo means eight, after all!)

3. If a figure has three sides, it is a triagle (not positive on this one)

4. symmetric property of congruence (this one's a simple search :p )

5. N/A (although I believe its angle BEC=124 degrees, as every other choice Is proven to be true)

6. congruent complements theorem (this is because we are given that 3 is a suppliment of 4. we are also given that 2=4. Based on this, then 1=3 is congruent based on 1 being suppliment of 2, 2=4, and 3 being a suppliment of 4)

7. N/A

8. N/A (the picture is too fuzzy for me to make any ideas)

I'm sorry I couldn't solve them all, but I hope this at least gets you somewhere! Have a great day!

8 0

2 years ago

Write an equation for the following: The difference of six and a number is equal to 36.

mylen [45]

Answer:

6-x=36

x=-30.........

6 0

4 years ago

1f f(x) = ***, g(x) = x+4, and h(x) - 3x-2, what is (nofog)(x)?

Stels [109]

Answer:

first option y + 7 = –(x + 6) is correct option

Step-by-step explanation:

7 0

3 years ago

the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant

Tamiku [17]

Answer:

The rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters is $24\pi \:\frac{cm^3}{s}$

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

$\frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}$
$\frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}$
The volume of a cone of radius r and height h is given by $V=\frac{1}{3} \pi r^2 h$

We want to find the rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

$\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]$

Substituting the values we know into the above formula:

$\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}$

5 0

4 years ago