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2 years ago

PLEASE ANSWER I AM BEGGING!!!!!!Type a simplified fraction as an answer.

Mathematics

3 answers:

Vesnalui [34]2 years ago

5 0

answer 5/6 decimal form is 0.83

bonufazy [111]2 years ago

3 0

Answer:

5/6

Step-by-step explanation:

100 ÷ 4 = 25

144 ÷ 4 = 36

Under root of 25 = 5

Under root of 36 = 6

Final Answer = 5/6

Hope this helps!

Sorry for the mistake before I did not see the under root!

joesaphine2 years ago

0 0

no sorry i do not know it

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Which multiplication expression is equal to 2 ÷ 1

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Answer:

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2 years ago

Describe a sequence of transformations that can be performed to polygon ABCDE to prove that it is similar to polygon FGHIJ

maxonik [38]

Answer:

answer below

Step-by-step explanation:

ABCDE go through dilation over center (6 , -2) with factor of 1/2 to FGHIJ

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2 years ago

Find all real numbers $s$ such that $-2(s - 7) > 4s + 8$. Give your answer in interval notation.

Stolb23 [73]

Answer:

$s\in (-\infty,1)$

Step-by-step explanation:

Solve the inequality $-2(s - 7) > 4s + 8$

Use distributive property:

$-2s+14>4s+8$

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Subtract 14:

$-6s+14-14>8-14\\ \\-6s>-6$

Divide by -6 (do not forget to change sign, because division by negative number changes the sign):

$s$

5 0

3 years ago

(PLEASE HELP) To feed 7 horses for 4 days, Mark needs 420 kg of grass. How many kilograms of grass does Mark need to feed 9 hors

DerKrebs [107]

Answer:

810kg is the answer

Step-by-step explanation:

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7 0

2 years ago

Read 2 more answers

Solve the equation on the interval [0,2π]

WARRIOR [948]

$\bf 16sin^5(x)+2sin(x)=12sin^3(x)
\\\\\\
16sin^5(x)+2sin(x)-12sin^3(x)=0
\\\\\\
\stackrel{common~factor}{2sin(x)}[8sin^4(x)+1-6sin^2(x)]=0\\\\
-------------------------------\\\\
2sin(x)=0\implies sin(x)=0\implies \measuredangle x=sin^{-1}(0)\implies \measuredangle x=
\begin{cases}
0\\
\pi \\
2\pi 
\end{cases}\\\\
-------------------------------$

$\bf 8sin^4(x)+1-6sin^2(x)=0\implies 8sin^4(x)-6sin^2(x)+1=0$

now, this is a quadratic equation, but the roots do not come out as integers, however it does have them, the discriminant, b² - 4ac, is positive, so it has 2 roots, so we'll plug it in the quadratic formula,

$\bf 8sin^4(x)-6sin^2(x)+1=0\implies 8[~[sin(x)]^2~]^2-6[sin(x)]^2+1=0
\\\\\\
~~~~~~~~~~~~\textit{quadratic formula}
\\\\
\begin{array}{lcccl}
& 8 sin^4& -6 sin^2(x)& +1\\
&\uparrow &\uparrow &\uparrow \\
&a&b&c
\end{array} 
\qquad \qquad 
sin(x)= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a}
\\\\\\
sin(x)=\cfrac{-(-6)\pm\sqrt{(-6)^2-4(8)(1)}}{2(8)}\implies sin(x)=\cfrac{6\pm\sqrt{4}}{16}
\\\\\\
sin(x)=\cfrac{6\pm 2}{16}\implies sin(x)=
\begin{cases}
\frac{1}{2}\\\\
\frac{1}{4}
\end{cases}$

$\bf \measuredangle x=
\begin{cases}
sin^{-1}\left( \frac{1}{2} \right)
sin^{-1}\left( \frac{1}{4} \right)
\end{cases}\implies \measuredangle x=
\begin{cases}
\frac{\pi }{6}~,~\frac{5\pi }{6}\\
----------\\
\approx~0.252680~radians\\
\qquad or\\
\approx~14.47751~de grees\\
----------\\
\pi -0.252680\\
\approx 2.88891~radians\\
\qquad or\\
180-14.47751\\
\approx 165.52249~de grees
\end{cases}$

3 0

3 years ago