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3 years ago

PLEASE ANSWER I AM BEGGING!!!!!!Type a simplified fraction as an answer.

Mathematics

3 answers:

Vesnalui [34]3 years ago

5 0

answer 5/6 decimal form is 0.83

bonufazy [111]3 years ago

3 0

Answer:

5/6

Step-by-step explanation:

100 ÷ 4 = 25

144 ÷ 4 = 36

Under root of 25 = 5

Under root of 36 = 6

Final Answer = 5/6

Hope this helps!

Sorry for the mistake before I did not see the under root!

joesaphine2 years ago

0 0

no sorry i do not know it

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3 years ago

Read 2 more answers

A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi

Margaret [11]

Answer:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=26Kg$

Step-by-step explanation:

Data

Brine a (Ba)

$V_{Ba}=5\frac{Lt}{min}\\ Concentration(Bca)=0.05\frac{Kg}{Lt}$

Brine b (Bb)

$V_{Bb}=10\frac{Lt}{min}\\ Concentration(Bcb)=0.04\frac{Kg}{Lt}$

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: $y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}$

Finally:

a) $y(t)=0.65\frac{Kg}{min}(tmin)$

b) $y(40)=0.65\frac{Kg}{min}(40min)=26Kg$

being y(t) the amount of salt (y) per unit of time (t)

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